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andreev551 [17]
4 years ago
11

How do stars radius compare with their mass

Physics
1 answer:
VladimirAG [237]4 years ago
3 0

Stars' radius is measured in length or distance units, such as inches or kilometers.

Their mass is measured in mass units, such as slugs or kilograms.

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Which elements symbol could replace the question mark in the diagram?
Kobotan [32]
Those dots represent the valence electrons of the element. The only elements with 6 valence electrons are oxygen, sulfur,  selenium, and..... so on. SO the answer to your question is B, tellurium(Te).
7 0
3 years ago
Read 2 more answers
A uniform meterstick in static rotational equilibrium when a mass of 220 g is suspended from the 5.0 cm mark, a mass of 120 g is
KatRina [158]

Answer:

m = 170 g

Explanation:

Meter stick is suspended at 40 cm mark

So here the torque due to additional mass and torque due to weight of the spring must be counter balanced

given that

1) 220 g is suspended at x = 5 cm

2) 120 g is suspended at x = 90 cm

3) mass of the scale is acting at its mid point i.e. x = 50 cm

now with respect to the suspension point the torque must be balanced

so we have

220(40 - 5) = m(50 - 40) + 120(90 - 40)

220(35) = 10 m + 6000

by solving above equation we have

m = 170 g

7 0
4 years ago
A block of mass 15 kg starts from rest and slides down a 20° angle inclined plane. the coefficient of kinetic friction is 0.3. a
ladessa [460]
The answer is 96 ..................................................
7 0
4 years ago
A couch of mass 210 kg is being pushed across the floor with an applied force of 4100 N. The coefficient of kinetic friction bet
Dennis_Churaev [7]
Let us use the formula for Newton's Second Law of Motion:

Net force = Mass*Acceleration
Net force = Applied Force - μ*Normal Force
where μ is the coefficient of kinetic friction

Normal Force = Force due to gravity = mass*gravity
Normal Force = (210 kg)(9.81 m/s²) =<em> 2,060.1 N</em>

Then,
Net force = 4100 - 0.38*2060.1 = 3317.162 N

3317.162 N = (210 kg)(a)
Solving for acceleration,
<em>a = 15.796 m/s²</em>
8 0
4 years ago
How many coulombs of positive charge are there in 3.60 kg of plutonium, given its atomic mass is 244 and that each plutonium ato
PtichkaEL [24]

1 mole of plutonium = 244 gm

3.6 kg of plutonium = 3.6 × 1000 = 3600 gm

Number of moles = 3600 ÷ 244 = 14.754 moles

One moles of plutonium contains protons = \( 6.023 \times {10}^{23} \times 94 \)

Total number of protons in 14.754 moles = \( 6.023 \times {10}^{23} \times 94 \times 14.754 \)

Total number of protons in 14.754 moles = \(8353.15 \times {10}^{23}\)

Total Positive charge = \(8353.15 \times {10}^{23} \times 1.6 \times {10}^{-19}\)

Total positive charge = \(13365.04 \times {10}^{4}\) C


3 0
4 years ago
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