Question

When the E string of a guitar (frequency 330 Hz) is plucked, the sound intensity decreases by a factor of 2 after 4 s. Determine

Answer 1

Answer:

$Q=50.3$

Explanation:

From the question we are told that:

Frequency $F=330Hz$

Sound intensity drop $I_d=2$

Time $T=4s$

Therefore

Sound intensity Ratio

 $\frac{I}{I_x}=\frac{1}{2}$

Generally the equation for Sound intensity is mathematically given by

 $\frac{I}{I_x}=e^{-4\ \=t}$

 $\frac{1}{2}=e^{-4\ \=t}$

 $\=t =5.8s$

Generally the equation for Quality Factor is mathematically given by

 $Q=2 \pi\frac{E}{\triangle E}$

 $Q=2 \pi\frac{E}{\frac{E}{2*4}}$

 $Q=50.3$