36÷6325=.0043243243
Hope this helps!
Answer:
a1 = 39, a2 = 41, a3 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Step-by-step explanation:
Let the first integer be a1 = a.
Let the second odd integer be a2 = a + 2
Let the third odd integer be a3 = (a + 2) + 2 = a + 4
The sum of three consecutive odd integers is 123.
123 = a1 + a2 + a3
123 = a + (a + 2) + (a + 4)
123 = 3a + 6
117 = 3a
a = 39
a1 = a = 39
a2 = a + 2 = 39 + 2 = 41
a3 = a + 4 = 39 + 4 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Answer:
d^-1(t)=t/70
Step-by-step explanation:
38inches 4x3/2=6+8x4=32 all together=38 inched
