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Pepsi [2]
2 years ago
15

At the start of a hike a hiker was at an elevation of -50 feet or zero represents sea level the hiker climbs at a rate of 15 fee

t per minute. Write an inequality that represents T the number of minutes after the start of the hike when the hikers elevation was higher than 5 feet above sea level explain or show your reasoning
Mathematics
1 answer:
JulijaS [17]2 years ago
7 0
-50 + 15T > 5

See the image for a breakdown of what these terms mean/how they’re measured!

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Paul wants a bike that cost $400. If he had saved 60% of this amount, how much had he saved.
enyata [817]
Hey!


To solve this problem, we'll first start by creating an equation.

<em>Our Created Equation :
</em>
\frac{400 x 60}{100}

Now we'll solve it step by step to find the answer.

So we should begin by multiplying the to portion of our fraction.

<em>400 x 60 = 24,000</em>

Next, we divide our answer by 100, since that is the next step to our equation.

<em>24,000 ÷ 100 = 240</em>

So, our answer is...

<em>Paul has already saved</em>  $240.00  <em>of the $400.00 he must pay for a new bike.</em>

Hope this helps!


- Lindsey Frazier ♥
4 0
3 years ago
Which of the following is a conjugate for 7 + iSquare root of 2?
olganol [36]
Conjugate of a complex number a + ib = a - ib.
Therefore, conjugate of 7 + isqrt(2) = 7 - isqrt(2)
6 0
3 years ago
Read 2 more answers
5 + 3 × 2 -6 the value needs to be 10
andriy [413]
5+3+2-6 is the value of 10 so yes you are correct
7 0
3 years ago
Read 2 more answers
What statement best explains whether y=3x +5 is a linear function or a nonlinear function?​
GarryVolchara [31]

Answer:

It is a linear function because its graph contains the points (0,5), (1,8), (2,11), which are on a straight line.

8 0
1 year ago
7.2.9-T Question Help Here are summary statistics for randomly selected weights of newborn girls: n= 157, x = 33.6 hg, s = 6.2 h
ch4aika [34]

Answer:

The 98% confidence interval estimate of the mean is between 32.45 hg and 34.75 hg.

32.3 is not a part of the confidence interval, which means that yes, these results are very different from the confidence interval 32.3 hg​

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.01 = 0.99, so Z = 2.327.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.327\frac{6.2}{\sqrt{157}} = 1.15

The lower end of the interval is the sample mean subtracted by M. So it is 33.6 - 1.15 = 32.45 hg

The upper end of the interval is the sample mean added to M. So it is 33.6 + 1.15 = 34.75 hg

The 98% confidence interval estimate of the mean is between 32.45 hg and 34.75 hg.

Are these results very different from the confidence interval 32.3 hg​

32.3 is not a part of the confidence interval, which means that yes, these results are very different from the confidence interval 32.3 hg​

6 0
2 years ago
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