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mote1985 [20]
2 years ago
9

What is the value of the expression below? ​ 2[3(16+)]-8

Mathematics
1 answer:
sladkih [1.3K]2 years ago
5 0

Answer:

<h2><u><em>94</em></u></h2>

Step-by-step explanation

2 * [3 * (16 + 1)] - 8 =

2 * [3 * 17] - 8 =

2 * 51 - 8

102 - 8 =

94

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Can someone help :-)
Ostrovityanka [42]
Hey,here is the answer to your question;
In part A:
Coefficient =20
Variable =c
Constant =35 and 23.50


In part B:
Savings=20*3+23.5+35*12
=> savings=$503.5.


In part C:
The new expression will be :25c+35+23.5

Hope this helps u!!!!..
6 0
3 years ago
Use the distributive property to write an experssion that is equalent to 7(3x-4)
photoshop1234 [79]

Answer:

21x-28

Step-by-step explanation:

the distributive property states that a(bx+c) is equal to abx+ac. in this expression, a is 7, b is 3, and c is negative 4. ab is 7*3, which is 21, so abx is 21x. ac is 7*-4, which is -28. combining these two results in 21x-28.

6 0
2 years ago
Read 2 more answers
If f(x) = 5x, what is fr¹(x)?
Anna [14]

Answer:

The first one

Step-by-step explanation:

3 0
2 years ago
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If lines m and n are parallel, and 5 measures 120o, which is the measure of 3?
Ierofanga [76]
If angle 3 is adjacent (right next to) angle 5, then its measure would be 60 degrees.  If angle 3 is congruent (vertical or alternate interior/exterior) to 5, it is 120.
3 0
3 years ago
write the standard form of the equation of the circle for which the endpoints of a diameter are (0,0) and (4,-6)
Elenna [48]

Given:

The endpoints of a diameter are (0,0) and (4,-6).

To find:

The equation of the circle.

Solution:

The endpoints of a diameter are (0,0) and (4,-6). So, the length of the diameter is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-0)^2+(4-0)^2}

d=\sqrt{36+16}

d=\sqrt{52}

d=2\sqrt{13}

Now, radius is half of the diameter.

r=\dfrac{2\sqrt{13}}{2}

r=\sqrt{13}

Center of the circle is the midpoint of the endpoints of a diameter.

Center=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Center=\left(\dfrac{0+4}{2},\dfrac{0+(-6)}{2}\right)

Center=\left(\dfrac{4}{2},\dfrac{-6}{2}\right)

Center=\left(2,-3\right)

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is radius.

The center of the circle is (2,-3) and radius is \sqrt{13}. So,

(x-2)^2+(y-(-3))^2=(\sqrt{13})^2

(x-2)^2+(y+3)^2=13

Therefore, the standard form of the circle is (x-2)^2+(y+3)^2=13.

5 0
2 years ago
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