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3 years ago

What value of r makes –6r + 2(r + 2) – 5 = -20 true?

1 answer:

4 0

Hello!

To find the answer we need to solve for r. First we undo the parentheses.

-6r+2r+4-5=-20

Now we combine like terms.

-4r-1=-20

We add one to both sides.

-4r=-19

Divide both sides by -4.

r=4.75

I hope this helps!

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What’s 1.2983 rounded to the nearest hundredth

KengaRu [80]

1.30 :)
All you have to do is see if the number on your left is greater than 5 or not if it’s is round up 1 if not it stays the same !
Hope this helped !!!

3 0

2 years ago

A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?

Ivan

Answer:

1/12

Step-by-step explanation:

Okay, so this will be a compound probability question because there are two parts to the question.

Firstly, a die has 6 sides, and there is only one chance of getting a 1, so the probability would be 1/6.

Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.

6 0

3 years ago

Read 2 more answers

I need help asap. Evaluate Expressions

Anit [1.1K]

Answer:

p-r/6=-6-(-6)/6=-6+1=-5

2:

p-(m-n)= -1-(-4-4)=-1-(-8)=-1+8=7

(z+y)/2)3=(-5-4)/3=-9/3=-3

4:

m/6-n=6/6-6=1-6=-5

k³-h=3³-(-2)=27+2=29

p-(p-(m-3))=5-(5-(4-3))=5-(5-1)=5-4=1

(k)(k-j)+3=(5)(5-5)+3=5*0+3=3

p²/6-q=6²/6-4=6-4=2

9;

zx+3³=6*4+3³=24+27=51.

10:

y+z-(y-x)=5+4-(5-2)=9-3=6

Some basic rules:

+. +. +=+

+. * +=+

+. ÷ +=+

+. - +=+

and

+. +. -=add and put sigh of greater one.

-. * +=-sigh

-÷-=+sigh

- - -=add and put - sigh

7 0

2 years ago

Read 2 more answers

E = mc2.

STALIN [3.7K]

#Equation of m?

<h3>Equation</h3>

m = E/c²

E = mc²

E : c² = m

E/c² = m

So, the formula of m is E/c²

8 0

2 years ago

A sphere with a radius of 4 cm is enlarged by a scale factor of 2. What is the approximate volume of the new sphere in cubic cen

Lisa [10]

$\textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ \stackrel{original}{r=4}\\ \stackrel{enlarged}{r=(4)(2)} \end{cases}\implies \begin{array}{llll} V=\cfrac{4\pi (\stackrel{enlarged}{~~(4)(2)~~})^3}{3} \\\\\\ V=\cfrac{2048\pi }{3}\implies V\approx 2144.66~cm^3 \end{array}$

5 0

1 year ago