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aleksandr82 [10.1K]
2 years ago
15

5 sweets cost 30p altogether, how much do 7 sweets cost?

Mathematics
2 answers:
marshall27 [118]2 years ago
6 0
5 sweets cost 30p.
1 sweet would cost = 30/5 = 6p.
7 sweets would then cost = 7 * 6 = 42p.


Nezavi [6.7K]2 years ago
4 0
The best way to find out what 7 sweets cost, firstly, you should find out what one sweet would cost. You have 5 sweets, with a total cost of 30p. You should divide 30 by 5, giving you 6p per sweet. To get the cost of 7 sweets, you have to multiply 6p by 7, giving you 42p. Therefore, the cost of 7 sweets is 42p. Hope this helps :)
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One card is selected at random from a deck of card. Determine the probability that the card selected is not a 4
Ganezh [65]

Answer:

12/13

Step-by-step explanation:

A probability is the number of desired outcomes over the total number of outcomes.

Assuming that this is a standard deck of playing cards, there will be 52 cards, and there will be 4 "4" cards.

First, find the number of desired outcomes, and put it over the total number of outcomes.

Out of the total number of outcomes (52), there are 4 outcomes that are not wanted, hence the equation is:

52 - 4 = 48

So out of the 52 possible outcomes, 48 are desired. Set up the fraction and

simplify:

48/52

/4   /4

= 12/13

7 0
3 years ago
Dan drank 7/8 of a bottle of
Anika [276]

Answer:

Dan drank  1 3/8 ths of the bottle of water

Step-by-step explanation:

since the question is asking how much water he drank altogether, it wants you to add

so

7/8+4/8=11/8

Dan drank 11/8 ths of the bottle of water (1  3/8)

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Step-by-step explanation:

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2 years ago
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According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
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