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3 years ago

9

Lisa plays basketball and her shooting accuracy increased by 10% from 2001 to 2002, and by 30% from 2002 to 2003. By what percen

t did her shooting accuracy increase from 2001 to 2003

1 answer:

goldenfox [79]3 years ago

7 0

Answer:

40%

Step-by-step explanation:

i believe because 10 from 2001 and bc of 2003 10 added by 30 is 40 percent sorry if wrong

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Answer:

The homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

Step-by-step explanation:

The general form of the linear regression equation is:

$y=a+bx$

Here,

<em>y</em> = dependent variable = test grade

<em>x</em> = independent variable = homework grade

<em>a</em> = intercept

<em>b</em> = slope

Compute the value of <em>a</em> and <em>b</em> as follows:

$a=\frac{\sum Y\cdot \sum X^{2}-\sum X\cdot\sum XY}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(592\times 44909)-(591\times45227)}{(8\times44909)-(591)^{2}}\\\\=-14.316$ $b=\frac{n\cdot \sum XY-\sum X\cdot\sum Y}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(8\times 45227)-(591\592)}{(8\times44909)-(591)^{2}}\\\\=1.195$

The linear regression equation that represents the set of data is:

$y=-14.316+1.195x$

Compute the value of <em>x</em> for <em>y</em> = 68 as follows:

$y=-14.316+1.195x$

$68=-14.316+1.195x\\1.195x=68+14.316\\1.195x=82.316\\x=68.884\\x\approx 69$

Thus, the homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

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