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Bad White [126]
2 years ago
6

PLEASE HELP I WILL HELP YOU

Mathematics
1 answer:
Sidana [21]2 years ago
7 0

Answer:

5 is the answer

Step-by-step explanation:

hope this helps

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7 more than the product of a number and 4 is 51 what is the number? A.4 B.5 C.13 or D.11
Rasek [7]
I would say 13 would be your answer. Hope this helps!
4 0
3 years ago
Sam has 8 quarters, 5 dimes, and 3 Nicole's in his pocket. If one coin is selected random, what is the probability that it will
Murrr4er [49]
There are a total of 16 coins, so out of the ratio, that 16 goes on the bottom.  Now you have to add up the coins that are NOT quarters and that number goes on the top.  So your ratio is 8/16 or 1/2
6 0
3 years ago
Which of the following systems of inequalities has solutions represented by the graph shown below?
Digiron [165]

Answer:

y ≤ 1/2x - 1

y ≤ -2x + 4

7 0
2 years ago
Help me please, Find a, b, and c.
Mama L [17]

Answer:

a = 6*\sqrt{3}

b = 12

c = 6\sqrt{2}

Step-by-step explanation:

Since the triangles are right triangles with 60 and 45 degree angles, their side lengths follow special triangles.

A 45-45-90 right triangle has side lengths 1-1-\sqrt{2}.

A 30-60-90 right triangle has side lengths 1 - \sqrt{3} -2.

Starting with the top triangle which has a 60 degree angle, its side length 6 corresponds to a side length of 1 in the special triangle. It is 6 times bigger so its remaining sides will be 6 times bigger too.

Side a corresponds to side length \sqrt{3}. Therefore, a = 6*\sqrt{3}.

Side b corresponds to side length 2, b = 2*6 = 12.

The bottom triangle has a 45 degree angle, its side length b= 12 corresponds to \sqrt{2}. This means \sqrt{2} was multiplied by 12 = \sqrt{2} * \sqrt{72}. This means that side c is \sqrt{72}=6\sqrt{2}.

3 0
3 years ago
Read 2 more answers
1. A square ABCD has the vertices A(n, n), B(n, -n), C(-n, -n), and D(-n, n). Which vertex is in Quadrant III?
andrew-mc [135]

The four quadrants and the sign of coordinates is given as follows:

Quadrant I : (n, n ) both x and y positive.

Quadrant II : ( -n,n) = x negative and y positive.

Quadrant III : ( -n,-n) = both x and y negative.

Quadrant IV: (n, -n) = x positive and y negative.

So Based on the above concept , we can say that vertex C (-n,-n) has both x and y negative and so it lies in quadrant III.

Answer is Vertex C (-n,-n)

5 0
3 years ago
Read 2 more answers
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