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3 years ago

The discount price of a hat is $18.00 what is the regular price?

Mathematics

1 answer:

noname [10]3 years ago

5 0

You gotta put more information out buddy

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Please help!!! ill mark brainliest

Vesnalui [34]

3x - 1 = 3x + 1

subtract 3x from both sides to get (-1 = 1). This is a false statement so it is: CONTRADICTION

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4x - 11 = 7

add 11 to both sides and then divide both sides by 4 to get $(x = \frac{18}{4} = \frac{9}{2})$ . This statement is true only when x = $\frac{9}{2}$ so it is: CONDITIONAL

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2 - 8x = 2 - 8x

add 8x to both sides to get (2 = 2). This is a true statement so it is: IDENTITY

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x + 1 = -x + 4

add x to both sides, subtract 1 from both sides, and divide both sides by 2 to get $(x = \frac{3}{2} )$ . This statement is true only when x = $\frac{3}{2}$ so it is: CONDITIONAL

Answer: B, A, C, A

6 0

3 years ago

Match the exponential expression with its rule:

mina [271]

1.=d
2.=a
5.=b
4.=e
3.=c

6 0

4 years ago

Jamie puts $500 into a savings account that has an interest rate of 1% how much will be in her account after 6 years?

IgorLugansk [536]

Step-by-step explanation:

interest:

$500 \times \frac{1}{100} \times 6 = 30$

Total=500+30=530

4 0

3 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

6 0

3 years ago

Can anyone help me with primary 5 hw ?

Illusion [34]

B) 28×50, then take the answer - 1100

5 0

3 years ago