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3 years ago

What is the inverse of the function f(x) = 2x+1

Mathematics

1 answer:

astra-53 [7]3 years ago

5 0

The inverse is f(x)=2x-1. Because the inverse operation of addition is subtraction.

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Find the product. (–7t – 5v)(–4t – 3v)

Anuta_ua [19.1K]

Answer: Option B is the correct answer

Step-by-step explanation:

The given expression is

(–7t – 5v)(–4t – 3v).

The product will be a quadratic equation (having 2 as the highest power)

To find the product, we would expand the brackets

(-7t × -4t )+ (-7t × -3v) + (-5v × -4t) + (-5v × - 3v)

= (- -28t^2) +(- -21tv) + (- - 20tv) +(- -15v^2)

Recall, negative × negative equals positive.

=28t^2 +21tv +20tv+ 15v^2)

Collecting like terms, we add all terms containing the same letters together

28t^2 + 41tv + 15v^2

Option B is the correct answer

7 0

3 years ago

If all of the diagonals are drawn from a vertex of a quadrilateral, how many triangles are formed?

sergij07 [2.7K]

Answer:

Step-by-step explanation:

From the chioces give it would be 4

But it is actually 8

8 0

2 years ago

A spa employs 54 people. Management wants to gather data about current and future services for clients. A random sample of 22 em

Igoryamba

Answer:

Step-by-step explanation:

i choose (c) because that the answer

5 0

3 years ago

Solve for x. leave your answer in simplest radical form.

adell [148]

Answer:

could you provide the equation for which x is to be solved?:)...If your question was supposed to be that ...then hope the solution helps:)

8 0

2 years ago

PLEASE PLEASE HELP! Find the measure of APB^.

Whitepunk [10]

Answer:

65°

Step-by-step explanation:

Radii CA and CB are perpendicular to tangent lines AT and BT, so

$\angle CAT=\angle CBT=90^{\circ}$

Since angle BAT is equal to 65°, angle CAB has measure

$\angle CAB=90^{\circ}-65^{\circ}=25^{\circ}.$

Consider triangle ACB. This triangle is isosceles, because CA=CB as radii of the circle. Two angles adjacent to the base are congruent, thus

$\angle CBA=\angle CAB=25^{\circ}$

The sum of the measures of all interior angles in triangle is always 180°, so

$\angle CAB+\angle CBA+\angle ACB=180^{\circ}\\ \\25^{\circ}+25^{\circ}+\angle ACB=180^{\circ}\\ \\\angle ACB=130^{\circ}$

Angle ACB is central angle subtended on the minor arc AB, angle APB is inscribed angle subtended on the same minor arc AB. The measure of inscribed angle is half the measure of central angle subtended on the same arc, so

$x=\angle APB=\dfrac{1}{2}\cdot 130^{\circ}=65^{\circ}$

8 0

3 years ago