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Sladkaya [172]
3 years ago
13

Find the value of y when x equals -1. 8x - 2y =10

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

y = - 9

Step-by-step explanation:

Substitute in -1 for x

8(-1) - 2y = 10

-8 - 2y = 10

Subtract -8 from both sides

-8 - (-8) cancels out to 0

10 - (-8) = 18

We are left with:

-2y = 18

Divide by -2 on both sides.

-2y/-2 = y

18/-2 = -9

y = -9

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Triangle ΔABC has side lengths of a = 18, <img src="https://tex.z-dn.net/?f=b%3D18%5Csqrt%7B3%7D" id="TexFormula1" title="b=18\s
ozzi

The measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

<h3 /><h3>What is the law of cosine?</h3>

When the three sides of a triangle is known, then to find any angle, the law of cosine is used.

It can be given as,

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle B=\cos^{-1}\left(\dfrac{a^2+c^2-b^2}{2ac}\right) \\\angle C=\cos^{-1}\left(\dfrac{a^2+b^2-c^2}{2ab}\right)

Here, a,b and c are the sides of the triangle and A,B and C are the angles of the triangle.

Triangle ΔABC has side lengths of a = 18, b=18√3  and c = 36 inches.

  • Part A: Determine the measure of angle A

Put the value, in the cosine law, the measure of angle A.

\angle A=\cos^{-1}\left(\dfrac{b^2+c^2-a^2}{2bc}\right) \\\angle A=\cos^{-1}\left(\dfrac{(18\sqrt{3})^2+36^2-18^2}{2(18\sqrt{3})(36)}\right) \\\angle A=0.5236\rm\; rad\\\angle A=30^o\rm\; degree\\

  • Part B: Show how to use the unit circle to find tan A

Using the chart of unit circle, the value of tangent A can be found out. The tangent A is,

\tan A=\tan 30^o\\\tan A=\dfrac{1}{\sqrt{3}}

  • Part C: Calculate the area of ΔABC.

Use the following formula to find area of ΔABC.,

A=\dfrac{ab.\sin C}{2}\\A=\dfrac{18\times18\sqrt{3}.\sin C}{2}\\A=280.6\rm\; in^2

Thus, the measure of angle A is 30 degree, the value of tan A is 1/√3 and the area of triangle ABC is 280.6 squared inches.

Learn more about the law of cosine here;

brainly.com/question/4372174

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