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3 years ago

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Rectangle pqrs is shown with its diagonals, pr and qs. what type of triangle is △str?right triangleequilateral triangleisosceles

trianglescalene triangle

2 answers:

Rainbow [258]3 years ago

8 0

Since you did not provide a diagram, I made one for easier reference. You are asking what kind of triangle is the one shaded in red. Since a rectangle has two sets of congruent sides, their diagonals are also equal. When two diagonals intersect each other, they make 4 congruent sides. Thus, the triangle is an isosceles triangle, since it has two equal sides ST and TR.

Yanka [14]3 years ago

3 0

Answer:isosceles

Step-by-step explanation:

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For y = 3x - 2x^2 +5x^3<br> show how to find the value for y, when x = 3. Show your work

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$y \: = \: f(x) \: = \: 3x \: - \: 2 {x}^{2} \: + \: 5 {x}^{3}$
Here, y is a cubic function of x.
When x = 3,
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$y \: = \: 9 \: - \: 18 \: + \: 135$
$y \: = \: f(3) \: = \: 126$
Hence, when x = 3, y = 126.

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What is 9,349 rounded to the nearest thousand?

zlopas [31]

Answer:

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Step-by-step explanation:

since the hundreds value is under 5, you round down and it will round the thousands value to 9000

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Jeanine baker makes floral arrangements. She has 12 different cut flowers and plans to use 5 of them. How many different selecti

Alona [7]

Assuming that the order of selection is not important, this is a question of number of ways. In other words, the combination should be computed. That is,

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3 years ago

Find the distance between each pair points (-5,3) , (-4,-5)?

MrRa [10]

Answer:

$\sqrt{65}$

Step-by-step explanation:

distance between two points:

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3 years ago

Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2

Nana76 [90]

Answer: $k=18\dfrac{8}{11}$ .

Step-by-step explanation:

If a line passing through two points, then

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN $=\dfrac{1-0}{5-0}=\dfrac{1}{5}$

The endpoints of segment AB have coordinates $\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)$ and $\left(-2\dfrac{1}{4} , k\right)$ .

$A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)$

$B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right)$ .

Slope of AB $=\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}$

$=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}$

$=\dfrac{4k-9}{4}\times \dfrac{44}{-145}$

$=4k-9\times \dfrac{11}{-145}$

$=\dfrac{44k-99}{-145}$

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

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$\dfrac{44k-99}{-725}=-1$

$44k-99=725$

$44k=725+99$

$k=\dfrac{824}{44}$

$k=\dfrac{206}{11}$

$k=18\dfrac{8}{11}$

Therefore, the value of k is $k=18\dfrac{8}{11}$ .

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3 years ago

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