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Neporo4naja [7]

3 years ago

10

Bethanine left at 3:00 in the afternoon and walked 3/10 of a mile to Bridget's house. Laney walked 36/100 of a mile to Bridget's

house. How far did Bethanie and Laney walk altogether? Determine if there is extra or missing inform

1 answer:

jarptica [38.1K]3 years ago

8 0

Answer:

Bethanie and Laney walked a total of = 0.66 miles or ( $\frac{33}{50}$ th of a mile)

Step-by-step explanation:

Bethanie walked 3/10th of a mile

Laney walked 36/100th of a mile

Lets divide and convert them to decimal:

3 divided by 10 gives us 0.30

36 divided by 100 gives 0.36

Total they walked:

0.30 + 0.36 = 0.66 miles

That would be (in fraction):

66/100 = 33/50 of a mile

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1) True 2) False

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1) Given $\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}$

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Expanding the summation we get

$\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}$

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Verify the above equality is true or false

Now find $\sum\limits_{k=0}^4\frac{3k+3}{k+6}$

Expanding the summation we get

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}$

$\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}$

now find $\sum\limits_{i=1}^3\frac{3i}{i+5}$

Expanding the summation we get

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}$

$\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}$

Comparing the series we get that the given equality is false.

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