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vfiekz [6]
2 years ago
8

Brendan's original plan was to visit stuttgart, dresden, weisbaden, and berlin. however, he would like to keep his costs under €

860. which change to brendan’s travel plans would result in his staying under, but closest, to his original budget? a. replace dresden with potsdam. b. replace stuttgart with kiel. c. replace berlin with munich. d. replace weisbaden with hanover.
Mathematics
1 answer:
Bond [772]2 years ago
6 0

Brendan's trip plans could be changed to keep him under, but near to, his original budget if he replaces Stuttgart with Kiel. Therefore, it is B.

<h3>What exactly is a budget?</h3>

A budget is basically a financial forecast of revenue and spending for a given period.

The substitution of Kiel for Stuttgart in Brendan's trip plans would result in him keeping under, but near to, his original budget. This will help save money.

Learn more about budget on:

brainly.com/question/6663636

#SPJ4

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A survey found that​ women's heights are normally distributed with mean 63.2 in. and standard deviation 2.4 in. The survey also
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Answer: 99.51%

Step-by-step explanation:

Given : A survey found that​ women's heights are normally distributed.

Population mean : \mu =63.2  \text{ inches}

Standard deviation: \sigma= 2.4\text{ inches}

Minimum height = 4ft. 9 in.=4\times12+9\text{ in.}=57\text{ in.}

Maximum height = 6ft. 2 in.=6\times12+2\text{ in.}=74\text{ in.}

Let x be the random variable that represent the women's height.

z-score : z=\dfrac{x-\mu}{\sigma}

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Now, by using the standard normal distribution table, we have

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3 years ago
A. Lin is using the diagram to prove the statement, "If a parallelogram has one
BigorU [14]

The congruence of the angles and triangles are proven as follows;

a. The composition angles of FGH are alternate interior angles to the composition angles of angle AHEF

b. The three sides of triangle ∆EHG are congruent to the three sides of triangle ∆GFE, therefore, triangles ∆EHG and ∆GFE are congruent by SSS congruency rule

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The lengths of the three sides of triangles that are congruent.

a. The shape of quadrilateral EFGH = A parallelogram

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Angle HEF = 90°

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Angle HED = angle FGD

Angle DEF is congruent to angle DGH (Alternate interior angles theorem)

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Therefore, the statement that will help prove angle FGH is also a right is that angle FGH is the sum of angles FGD and angle DGH which are alternate interior angles to angles HED and DEF which makes up angle HEF, which is a right angle.

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Statement. Reason

EF is congruent to HG. Opposite sides of a parallelogram are congruent

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