All categories

2 years ago

Suppose 20% of 300 students choose recycling. How many students choose

Mathematics

2 answers:

GrogVix [38]2 years ago

8 0

Answer:

around 60 kids chose to recycle

Step-by-step explanation:

20% of 300 = 60

Genrish500 [490]2 years ago

4 0

Answer:

Step-by-step explanation:

20% of 300

= $\frac{20}{100}$ × 300

= 0.2 × 300

= 60

You might be interested in

Find the length of the line segment formed by the points (2, 3) and (2, 5)

SCORPION-xisa [38]

Answer:

2 units

Step-by-step explanation:

Given data

The points are (2, 3) and (2, 5)

x1= 2

y1= 3

x2= 2

y2= 5

substitute into the distance between two points formula

d=√((x_2-x_1)²+(y_2-y_1)²)

d=√((2-2)²+(5-3)²)

d=√(2)²)

d=√4

d= 2 units

Hence the length is 2 units

3 0

3 years ago

HELP PLEASE

Jet001 [13]

Answer:

c $11,751

Step-by-step explanation:

The function that models Alicia's car is

$f(x) = 21000(0.93)^{x}$

where x represents the number of years since she purchased the car.

We want to find the value of Alicia's car after 8 years.

We substitute x=8 into the formula to get:

$f(8) = 21000(0.93)^{8}$

$f(8) = 21000(0.5596)$

$f(8) = 11751.218$

We round to the nearest dollar to get:

$f(8) =11751$

The correct answer is C.

5 0

3 years ago

A\b=c for bsolve for b and show your steps.show all steps.

Rufina [12.5K]

A/b=c
times both sides by b
A=bc
divide both sides by c
A/c=b
b=A/c

6 0

3 years ago

A rectangle has its vertices at (-4, -3), (-4,7), (1,7), (1, -3). What part, in percent, of the rectangle is located in Quadrant

Rasek [7]

Consider the attached figure. The whole rectangle is ABCD, while AEGF is the part located in the third quadrant. In fact, this quadrant is composed by all the points with both coordinates negative.

To answer the question, let's compute the area of the two rectangles and see what part of ABCD is AEGF.

A and B have the same x coordinate, so the length of AB is given by the absolute difference of their y coordinates:

$\overline{AB} = |A_y-B_y| = |-3-7| = |-10| = 10$

Similarly, but exchanging the role of x and y, we compute the length of BC:

$\overline{BC} = |B_x-C_x| = |-4-1| = |-5| = 5$

So, the area of the rectangle is $\overline{AB} \cdot \overline{BC} = 10\cdot 5 = 50$

The same procedure allows us to compute width and height of the sub-rectangle in the third quadrant:

$\overline{AE} = |A_y-E_y| = |-3-0| = |-3| = 3$

$\overline{EG} = |E_x-G_x| = |-4-0| = |-4| = 4$

So, the area of the portion located in the third quadrant is $\overline{AE} \cdot \overline{EG} = 3\cdot 4 = 12$

This means that the ratio between the two area is

$\cfrac{\text{area }AEGF}{\text{area }ABCD} = \cfrac{12}{50}$

If we want this ratio to be a percentage, just make sure that the denominator is 100:

$\cfrac{12}{50} = \cfrac{12}{50}\cdot \cfrac{2}{2} = \cfrac{24}{100} = 24\%$

3 0

3 years ago

A circular plot with a 160 foot diameter is watered by a spray irrigation system. To the nearest square foot, what is the area t

Anuta_ua [19.1K]

A circular plot is watered by a sprinkler that rotates through it. The sprinkler only rotates through a semi-circle, or half of the whole circle.

Area of a circle: A = pi x r^2

r = 160 / 2 = 80

A = pi x 80^2

A = 6400pi / 2 = 3200pi

3200pi = 10053.0965

The area water is approximately 10,053 ft^2.

Hope this helps!! :)

4 0

3 years ago