bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient
A square is cut into two congruent triangles by drawing the diagonal between two corners. If the area of each triangle is 162 cm
,what is the length of the side of the square?
1 answer:
Ok so area=162
since the triangles sides were cut out of a square, base=height
area=1/2bh=162
b=h
area=1/2b^2=162
times 2 both sides
b^2=324
sqrt both sides
b=18=h
the legnth of one side is 18cm
see diagram
another way, is total aera of square=areas of both triangles=162+162=324
remember area of square=side^2 so
324=side^2
sqrt both sides
18=side
answer is 18cm
since the triangles sides were cut out of a square, base=height
area=1/2bh=162
b=h
area=1/2b^2=162
times 2 both sides
b^2=324
sqrt both sides
b=18=h
the legnth of one side is 18cm
see diagram
another way, is total aera of square=areas of both triangles=162+162=324
remember area of square=side^2 so
324=side^2
sqrt both sides
18=side
answer is 18cm
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For this case we have that the area of the triangle is given by:
Where:
b: It's the base
h: It's the height
We have to:
The atura will be given by:
So, the area is:
Answer:
144