Question

Solution for this one step by step please

Answer 1

Answer:

$D.\:\:\:\:\:\sec^4\theta$

Step-by-step explanation:

• $\frac{1+\tan^2\theta}{\cos^2\theta}$

• $=\frac{\sec^2\theta}{\cos^2\theta}\:\:\:(\because 1+\tan^2\theta=\sec^2\theta)$

• $=\sec^2\theta.\frac{1}{\cos^2\theta}$

• ${=\sec^2\theta.{\sec^2\theta}}\:\:\:(\because\frac{1}{\cos^2\theta}=\sec^2\theta)$

• $=\sec^4\theta$

Hope it helps you in your learning process.

Answer 2

Answer:

D

Step-by-step explanation:

using the identities

1 + tan²Θ = sec²Θ and cosΘ = $\frac{1}{sec0}$ , then

$\frac{1+tan^20}{cos^20}$

= $\frac{sec^20}{\frac{1}{sec^20} }$

= sec²Θ × sec²Θ

= $sec^{4}$Θ