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3 years ago

Pls help me solve this thank you

Mathematics

1 answer:

Igoryamba3 years ago

5 0

Answer:

x=49

Step-by-step explanation:

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Which of these is an example of delayed purchasing?

ser-zykov [4K]

Answer:

paying for a drum set in six months and receiving the drum set today -apex

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Mr. McMillan and Ms. Burke are teaching their classes how to write in cursive. Mr. McMillan has already taught his class 8 lette

dybincka [34]

The number of weeks by which the students in both classes will know how to write the same number of letters will be 4 weeks.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Mr. McMillan and Ms. Burke are teaching their classes how to write in cursive.

Mr. McMillan has already taught his class 8 letters.

The students in Ms. Burke's class, who started the unit later, currently know how to write 12 letters.

Mr. McMillan plans to teach his class 4 new letters per week.

Ms. Burke intends to cover 3 new letters per week.

Eventually, the students in both classes will know how to write the same number of letters.

Then the number of weeks by which the students in both classes will know how to write the same number of letters will be

Let x be the number of the weeks and y be the total number of the letters.

Then the equation will be

y = 4x + 8 …1

y = 3x + 12 …2

Then by solving the equations 1 and 2, we have

x = 4 and y = 24

More about the linear system link is given below.

brainly.com/question/20379472

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4 0

2 years ago

Use cylindrical coordinates to evaluate the triple integral ∭ where E is the solid bounded by the circular paraboloid z = 9 - 16

4vir4ik [10]

Answer:

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

Step-by-step explanation:

The Cylindrical coordinates are:

x = rcosθ, y = rsinθ and z = z

From the question, on the xy-plane;

$9 -16 (x^2 + y^2) = 0 \\ \\ 16 (x^2 + y^2) = 9 \\ \\ x^2+y^2 = \dfrac{9}{16}$

$x^2+y^2 = (\dfrac{3}{4})^2$

where:

0 ≤ r ≤ $\dfrac{3}{4}$ and 0 ≤ θ ≤ 2π

∴

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} \int ^{9-16r^2}_{0} \ r \times rdzdrd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 z|^{z= 9-16r^2}_{z=0} \ \ \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} r^2 ( 9-16r^2}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} \int ^{\dfrac{3}{4}}_{0} ( 9r^2-16r^4}) \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( \dfrac{9r^3}{3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3r^3}-\dfrac{16r^5}{5}})|^{\dfrac{3}{4}}_{0} \ drd \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV = \int^{2 \pi}_{0} ( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) d \theta$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}}) \theta |^{2 \pi}_{0}$

$\iiint_E E \sqrt{x^2+y^2} \ dV =( 3(\dfrac{3}{4})^3}-\dfrac{16(\dfrac{3}{4})^5}{5}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{64}}-\dfrac{243}{320}})2 \pi$

$\iiint_E E \sqrt{x^2+y^2} \ dV =(\dfrac{81}{160}})2 \pi$

$\mathbf{\iiint_E E \sqrt{x^2+y^2} \ dV =\dfrac{81 \ \pi}{80}}$

4 0

3 years ago

Sweet noticed the ratio of long boards to short boards was 1:4. If there were 35 surfboards at the beach , how many were short b

andre [41]

So the ratio to longboard to short board is 1:4, the total of that ratio is 5. 35 ÷ 5 = 7. now we're going to take those ratios and multiply 1 × 7 = 7 and 4 × 7 = 28. Your final answer is B. to confirm your answer add 28 + 7.

7 0

3 years ago

Can some show the steps and the answer please I really need help tell me how you get it and the answer

Lana71 [14]

Answer:

Step-by-step explanation:

so this is about triangles.. sooo the following is a bit of helpful reminders that I keep on my computer to help me remember how to fit the trig functions to triangles.. I strongly suggest you copy it and keep it where you can look at it often.

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

I use this anytime I run into triangles or need some help with sin or cos

now the problem , 3 ladder 10, 12, & 15 feet. Alex wants to get to 8 feet.

the problems is also telling you that you can use t..... and then , the words are cut off.. but I know they were going to say Tan ... next.. :P

b/c Tan is how you figure out problems with the adjacent side and the opposite side. like this problem. Look at TOA above. use that to recall how the parts fit in the formula

Tan(∅) = Opp / Adj

they give us the Opp side of 8 feet in the problem

then they also tell us the Hyp of the triangle which is each of the ladders length. Then they ask us what is the Adj sides length?

So we also need to solve the triangle with the know hyp (ladder length).. uggg, this problem is long. Then we can solve the dist. from the wall or Adj side length.

it's two steps, if you want to think of it that way. You're supposed to be pretty confident with trig functions. I'm guessing this is a trig class.. right?

let's solve for the 3 different angles that the ladders make , each going to 8 feel. Obviously, nobody would really do this with a ladder they would just lean it against the wall . and if it's taller than where they want to climb, they would just go up part way. so anyway, find the 3 different angles.

look above to see which formula to use.

I like SOH b/c it seems to have all the pieces of the triangle we want to work with.

ladder 1 ( 10')

Sin(∅) = Opp / Hyp

Sin(∅) = 8 / 10

∅ = arcSin (4/5)

[ first, yes, I just reduced the fraction, then I did the arcSin on both sides, I think you might know how to do that already ? ]

∅ = 53.13010 °

( yes, I used my calculator to find that, calculators are okay to use when figuring out non standard angles )

ladder 2 (12')

Sin(∅) = 8/12

∅ = arcSin (2/3)

∅ = 41.81031°

ladder 3 (15')

Sin(∅) = 8/15

∅ = arcSin (8/15)

∅ = 32.230952°

now use our Tan function to find the Adjacent side which is the distance from the wall

Tan(∅)= Opp / Adj

Adj = Opp / Tan(∅)

( I did some quick algebra to move the side we want to solve for, now plug and chug all 3 angles )

ladder 1

Adj = 8 / Tan(53.13010)

Adj = 6.0000005

ladder 2

Adj = 8 / Tan(41.81031)

Adj = 8.94427

ladder 3

Adj = 8 / Tan(32.230952)

Adj = 12.688577

so the 10' ladder is 6 feet from the wall

the 12' ladder is 8.9 feet from the wall

the 15 foot ladder is 12.7 feet from the wall.

I really don't think that 15' ladder is going to stay on the wall.. if Alex climbs it... it's way way too far out... it will just fall straight down the wall :/ Maybe another math problem for the forces involved :P

5 0

3 years ago