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Pani-rosa [81]
3 years ago
6

Does anyone else agree that the answer for this family of curves question is E, dy/dx = x + y?

Mathematics
1 answer:
neonofarm [45]3 years ago
6 0
Yes this is the correct answer. The slope field shown is the differential equation dy/dx = x+y

All points along the line x+y = k, for some constant k, will have the same tangent slope k. For example, the line x+y = 0 will have every point with tangent slope 0 for the solution y(x). It may not be 100% clear, but this graph has horizontal tickmarks on the line x+y = 0, or the tickmarks are close to being horizontal. Using geogebra, I checked the others and they produced completely different graphs, which allowed me to rule them out.
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What is the slope of this line?
galina1969 [7]
The answer should be 1
4 0
3 years ago
Mischa wrote the quadratic equation 0=-x2+4x-7 in standard form. If a = -1, what is the value of c in her equation?
sp2606 [1]

Answer:

c = -7

Step-by-step explanation:

0 = -x² + 4x - 7

Compare to

ax² + bx + c

a = -1 , b = 4 , c = -7

3 0
3 years ago
Solve for x, and angle c
patriot [66]

9514 1404 393

Answer:

  x = 12.75

  ∠C = 51.75°

Step-by-step explanation:

The two marked angles are complementary, so ...

  (5x -12) +(3x) = 90

  8x = 102

  x = 102/8

  x = 12.75

__

C = (5x -12)° = (5(12.75) -12)°

  ∠C = 51.75°

__

<em>Check</em>

E = 3x = 38.25, then C+E = 51.75 +38.25 = 90 . . . . as it should

5 0
2 years ago
What is the measure of a Pentagon
Mashutka [201]

Answer:

5 sides.

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Unlike a triangle, which is 180°, also equal to a straight line, the length is equal to 540°.

6 0
3 years ago
Read 2 more answers
For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
2 years ago
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