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raketka [301]
1 year ago
7

Write and simplify an expression for the volume of a rectangular prism with length ℓ m, width 5 m, and height 6.5 m. What is the

volume if the length is 8.4 m?
Mathematics
1 answer:
Dominik [7]1 year ago
4 0

Step-by-step explanation:

V= 32.5ℓ (m^3)

when ℓ= 8.4 m , V= 273 m^2

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8 0
3 years ago
The data below shows the points scored and minutes played by six basketball players during the 2004-2005 season. The least squar
k0ka [10]

We assume data and prediction as question is incomplete

Answer and Step-by-step explanation:

Least squares regression line equations are used to model the relationship that exists between two variables, dependent and independent variables. The equation has the form y=a+bx where y is the dependent variable and x is independent variable, a is a constant and is the y intercept and b is the slope of the line. This relationship is then used to predict future outcomes.

Given that data for 2004-2005 for the basketball players are :

James- 20 points

John- 30 points

Chris- 50 points

Dave-15 points

Donaldson- 32 points

Richard -40 points

We predict the scores/points for James (for example) for the following year using the equation of the regression line y=0.79x+1544

We substitute his points x=20 I'm the equation:

Y=0.79*20+1544

=1599.8

The predicted value is 1599.8

5 0
2 years ago
Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
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