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2 years ago

7

Write and simplify an expression for the volume of a rectangular prism with length ℓ m, width 5 m, and height 6.5 m. What is the

volume if the length is 8.4 m?

1 answer:

Dominik [7]2 years ago

4 0

Step-by-step explanation:

V= 32.5ℓ (m^3)

when ℓ= 8.4 m , V= 273 m^2

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PLEASE HELP ME ASAP WILL NAME YOU BRAINIEST

aliina [53]

Answer:

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Step-by-step explanation:

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3 years ago

The low temperature in Anchorage, Alaska today was -4°F. The low

Orlov [11]

Answer:

67°F

Step-by-step explanation:

-4-63 = - 67°F

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3 years ago

Chris cut a rope into two pieces. One piece was 11.36 meters long and the other piece was 13.46 meters long. About how long was

rosijanka [135]

If you would like to know about how long was the rope before Chris cut it and you would like to round each length to the nearest tenth to estimate the total length of the original piece of rope, you can calculate this using the following steps:

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3 years ago

Read 2 more answers

A number is increased by 35%.<br> The result is 324

stich3 [128]

Answer:

240.74

Step-by-step explanation:

y=±x* $\frac{100+p}{100}$

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2 years ago

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard devi

Mekhanik [1.2K]

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean $\mu$ , standard deviation $\sigma$

n days:

This means that $s = \frac{\sigma}{\sqrt{n}}$

Applying the Central Limit Theorem to the z-score formula.

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of $Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$ , in which $\mu$ is mean amount of inches of rain and $\sigma$ is the standard deviation.

5 0

2 years ago