Answer: 29
Step-by-step explanation: You have 3+2 that = 5 then you get that 5 and x that by 6 that = 30 then you - 30 from 1 then you have 29
Sorry I was wrong, I didn’t mean to get it wrong.
Answer:
For this question there appears to be absolutely no association. The points are all over the place and there is not consistent factors at play here.
We assume data and prediction as question is incomplete
Answer and Step-by-step explanation:
Least squares regression line equations are used to model the relationship that exists between two variables, dependent and independent variables. The equation has the form y=a+bx where y is the dependent variable and x is independent variable, a is a constant and is the y intercept and b is the slope of the line. This relationship is then used to predict future outcomes.
Given that data for 2004-2005 for the basketball players are :
James- 20 points
John- 30 points
Chris- 50 points
Dave-15 points
Donaldson- 32 points
Richard -40 points
We predict the scores/points for James (for example) for the following year using the equation of the regression line y=0.79x+1544
We substitute his points x=20 I'm the equation:
Y=0.79*20+1544
=1599.8
The predicted value is 1599.8
Answer:
D.)
Step-by-step explanation:
The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts. You can graph the function and see when the graph crosses the x-axis or solve for the x-values. I will solve it via factoring and so:

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6. Now let's think about all the factors of 6 we have: 6×1 and 2×3. Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5? Actually we can say 6-1=5 and 2+3=5. Let's try both.
First let's use 6 and -1 and so:

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.
Now let's try 2 and 3 and so:

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:
Case 1:

Case 2:

So your zero's are when x=-2 and x=-3.
D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.
~~~Brainliest Appreciated~~~