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2 years ago

Write the equation of the line that passes through points (-7,8) and (4,-5)

Mathematics

2 answers:

VLD [36.1K]2 years ago

6 0

Answer:

y = -13/11x - 3/11

Step-by-step explanation:

First, find the slope of the line using the slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-5-8}{4-(-7)}\\m=-\frac{13}{11}$

Then, use the point-slope formula and substitute the values for the variables.

$y-y_1=m(x-x_1)\\y-8=-\frac{13}{11}(x-(-7))\\y-8=-\frac{13}{11}x-\frac{91}{11}\\y=-\frac{13}{11}x-\frac{3}{11}$

Alex2 years ago

5 0

Answer:

y=-3/11x+67/11

Step-by-step explanation:

y-8=-5-8/4--7(x--7)

y-8=-3/11(x+7)

11y-88=-3x-21

11y=-3x-21+88

11y=-3x+67

y=-3/11x+67/11

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Step-by-step explanation:

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Which values of m and b will create a system of equations with no solution? choose 1 options.

hichkok12 [17]

Answer:

The graph of a linear equation is a straight line. The "solution" to a system of two linear equations is the point where the two lines cross. If the two lines are parallel, they never cross; hence parallel lines have no solution. Two lines are parallel if they have the same slope (the m value in y = mx+b). One of your equations is y = -2x + (you left the y-intercept out). The slope is -2. So any line with a slope of m = -2 will be parallel to this line and will not cross it. The second line also needs a different value of b, the y-intercept. Otherwise it is the same line and every point is a solution. So if your equation is:

y = -2x + 1

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2 years ago

What is 5/9 as a decimal and percent?

ale4655 [162]

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3 years ago

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HELP I'M SOOOOOO ANGRYYYYY PLEASE HELPPPP<br>determine the values of X for which g(x) is defined

tiny-mole [99]

Answer: Any real number x as long as $x \ne 0$ and $x \ne -\frac{2}{3}$

In other words, anything but 0 or -2/3 is valid.

========================================================

Explanation:

Set the denominator equal to zero and solve for x

2(3x^2 + 2x) = 0

3x^2 + 2x = 0

x(3x + 2) = 0

x = 0 or 3x+2 = 0 .... zero product property

x = 0 or 3x = -2

x = 0 or x = -2/3

If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.

Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.

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