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3 years ago

Find the perimeter. Simplify your answer.

Mathematics

2 answers:

qaws [65]3 years ago

8 0

7y+10+7y+10+y-4

14y+20+y-4

15y+20-4

15y+16

answer= 15y+16

Eduardwww [97]3 years ago

4 0

Answer:

7y+10+7y+10+y-4=

(7y+7y+y)+(10+10-4)=

15y+16=

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John and Karen plan on building a garden in their new home. They plan on designing a rectangular garden with a perimeter of 70 f

valentinak56 [21]

Answer:

Length of the garden= 7 feet while the width =28 feet

Step-by-step explanation:

Let the length of the garden be L while the width represented as W

From the question, we deduce the following:

W = 4L

Perimeter = 2(L + W) = 70 feet .... substituting W = 4L into this equation gives

70 = 2(L + 4L)

70 = 2(5L)

70 = 10L ... dividing both sides by 10 gives

L = 7

Recall from the first equation that W = 4L

W = 4 * 7 =28

7 0

3 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th

Elena L [17]

Answer:

The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, a = $\sqrt{(3-0)^{2}+(4-0)^{2}}$

Or, a = $\sqrt{9+16}$

Or, a = $\sqrt{25}$

∴ a = 5 unit

Similarly

The measure of length BC = b = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, b = $\sqrt{(3-3)^{2}+(2-4)^{2}}$

Or, a = $\sqrt{0+4}$

Or, b = $\sqrt{4}$

∴ b = 2 unit

And

So, The measure of length CA = c = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

Or, c = $\sqrt{(3-0)^{2}+(2-0)^{2}}$

Or, c = $\sqrt{9+4}$

Or, c = $\sqrt{13}$

∴ c = $\sqrt{13}$ unit

Now, area of Triangle written as , from Heron's formula

A = $\sqrt{s\times (s-a)\times (s-b)\times (s-c)}$

and s = $\frac{a+b+c}{2}$

I.e s = $\frac{5+2+\sqrt{13}}{2}$

Or. s = $\frac{7+\sqrt{13}}{2}$

So, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}$

Or, A = $\sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}$

Or, A = $\frac{3}{2}$ × $\sqrt{1+\sqrt{13} }$

∴ Area of triangle = 1.5 $\sqrt{4.6}$

Hence The area of triangle for the given coordinates is 1.5 $\sqrt{4.6}$ Answer

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3 years ago

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3 years ago

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(4y 2 – 5y) + (3y – 7y 2) – (2y 2 + 6y – 5) Simplify.

Elan Coil [88]

Equation at the end of step 1 : (((4•(y2))-5y)+(3y-(7•(y2))))-((2y2+6y)-5) Step 2 :Equation at the end of step 2 : (((4•(y2))-5y)+(3y-7y2))-(2y2+6y-5) Step 3 :Equation at the end of step 3 : ((22y2 - 5y) + (3y - 7y2)) - (2y2 + 6y - 5) Step 4 : Step 5 :Pulling out like terms :

5.1 Pull out like factors :

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I hope tht help

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