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Tatiana [17]
2 years ago
5

HELPPPP y=1/8x+3 in standard form​

Mathematics
2 answers:
zubka84 [21]2 years ago
8 0
8 because the standard form
lidiya [134]2 years ago
4 0

Answer:

x-8y=-24

Step-by-step explanation:

Standard form of a linear equation:  Ax+By=C

(where A, B and C are integers, and A shouldn't be negative)

Given equation:

y=\dfrac{1}{8}x+3

Multiply both sides by 8:

\implies 8 \cdot y=8 \cdot \dfrac{1}{8}x+8 \cdot 3

\implies 8y=x+24

Subtract 8y from both sides:

\implies 8y-8y=x+24-8y

\implies 0=x+24-8y

Subtract 24 from both sides:

\implies 0-24=x+24-8y-24

\implies -24=x-8y

In standard form:

\implies x-8y=-24

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Answer:

x ∉ R

Step-by-step explanation:

x² = - 21

if x² < 0 => x ∉ R

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3 years ago
Jerry's motorcycle tank holds 6gallons of gas. There are 3 gallons of gas currently in the tank. How much more gasoline will
ioda

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It takes 3 more gallons to fill the tank.

Step-by-step explanation:

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3 years ago
The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
likoan [24]

Answer:

A)  3%

B)  Product A

Step-by-step explanation:

<u>Exponential Function</u>

General form of an exponential function: y=ab^x

where:

  • a is the initial value (y-intercept)
  • b is the base (growth/decay factor) in decimal form
  • x is the independent variable
  • y is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

<u>Part A</u>

<u>Product A</u>

Assuming the function for Product A is <u>exponential</u>:

f(x) = 0.69(1.03)^x

The base (b) is 1.03.  As b > 1 then it is an <u>increasing function</u>.

To calculate the percentage increase/decrease, subtract 1 from the base:

⇒ 1.03 - 1 = 0.03 = 3%

Therefore, <u>product A is increasing by 3% each year.</u>

<u>Part B</u>

\sf percentage\:change=\dfrac{final\:value-initial\:value}{initial\:value} \times 100

To calculate the percentage change in Product B, use the percentage change formula with two consecutive values of f(t) from the given table:

\implies \sf percentage\:change=\dfrac{10201-10100}{10100}\times 100=1\%

Check using different two consecutive values of f(t):

\implies \sf percentage\:change=\dfrac{10303.01-10201}{10201}\times 100=1\%

Therefore, as 3% > 1%, <u>Product A recorded a greater percentage change</u> in price over the previous year.

Although the question has not asked, we can use the given information to easily create an exponential function for Product B.

Given:

  • a = 10,100
  • b = 1.01
  • n = t - 1 (as the initial value is for t = 1 not t = 0)

\implies f(t) = 10100(1.01)^{t-1}

To check this, substitute the values of t for 1 through 4 into the found function:

\implies f(1) = 10100(1.01)^{1-1}=10100

\implies f(2) = 10100(1.01)^{2-1}=10201

\implies f(3) = 10100(1.01)^{3-1}=10303.01

\implies f(4) = 10100(1.01)^{4-1}=10406.04

As these values match the values in the given table, this confirms that the found function for Product B is correct and that <u>Product B increases by 1% per year.</u>

4 0
2 years ago
a A palm tree casts a 19 foot shadow. A beach umbrella in the sand next to the palm tree casts a 6.5 foot shadow. If the umbrell
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Read 2 more answers
A. What percent of data is greater than the 13th percentile?
Vladimir79 [104]

Answer:

a) Almost 87% of the distribution is greater than the 13th percentile.

b) This indicates that the distribution is symmetrical. This doesn't necessarily mean that the distribution is a normal distribution, but it is clear that the distribution is symmetrical.

c) This indicates that the distribution is rich skewed or positively skewed.

d) The third number that makes the mean 12 = 1.

e) The standard deviation is the square root of variance.

f) 3600 people that sat for the exam had a score at least as high as the 55th percentile's score.

Step-by-step explanation:

a) What percent of data is greater than the 13th percentile?

The percentile serves to group a data distribution into 100 equal spaces parts. It represents the value or the point below which a particular proportion of the distribution falls.

The 13th percentile thus represent a value or a point in the distribution that is higher than 13% of the distribution.

Hence, the percentage of data greater than the 13th percentile will be just about (100-13)%, almost 87% of the distribution will be greater than the 13th percentile.

b. If the mean, median, and mode for a data set are all the same, what can you conclude about the data’s distribution?

If all the three major measures of the centre of a distribution all coincide at the same point/value, it indicates that the distribution is symmetrical. This doesn't necessarily mean that the distribution is a normal distribution, but it is clear that the distribution is symmetrical.

c. If the mean is greater than the mode and median for a data set, what can you conclude about the data’s distribution?

The mean greater than the median and mode mean that distribution is rightly/positively skewed.

d. Mean of 3 numbers is 12. Two of them are 15 and 20. What is the third number?

The mean is the sum of variables divided by the number of variables

Mean = = (Σx)/N

x = each variable

Let the unknown third number be y

N = number of variables = 3

12 = (15 + 20 + y)/3

35 + y = 36

y = 36 - 35 = 1

e. What is the relationship between variance and standard deviation?

The variance is an average of the squared deviations from the mean.

The standard deviation is the square root of variance.

f. You scored in the 55th percentile on the GRE. If 8,000 people took the GRE, how many people had a score at least as high as your score?

Like I explained in (a), scoring 55th percentile mean that one has scored more than 55% of the people that sat for the exam.

So, the percentage of people that score as much as the 55th percentile will be the top (100-55)% of people thay sat for the exam.

45% of 8000 = 3600 people.

3600 people had a score at least as high as the 55th percentile's score.

Hope this Helps!!!

3 0
2 years ago
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