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vaieri [72.5K]
4 years ago
14

) After the first exam in a large course, the professor surveyed 14 randomly selected students to determine the relation between

the amount of time they spent studying for the exam and exam score.  She found that a linear relation exists between the two variables.  The least-squares regression line that describes this relation is .
          (a) Predict the exam score of a student who studied 2 hours.

          (b) Write an interpretation for the slope. (Refer to Lesson 12.2 for this.)

          (c) Write an interpretation for the y-intercept, if appropriate. If not appropriate, explain why not. (Again, refer to Lesson 12.2 for this.)

 

2) In what scenarios would it not make sense to interpret the y-intercept?
Mathematics
1 answer:
olga_2 [115]4 years ago
3 0

C would be your answer, hope this helps!!

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5.125 divided by 7.1
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0.72

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12 and a half to a percent IS 1250%

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A bicycle shop advertised all mountain bikes priced at a 1/3 discount what is the amount of the discount if the bicycle original
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3 years ago
Consider a melody to be 7 notes from a single piano octave, where 2 of the notes are white key notes and 5 are black key notes.
igor_vitrenko [27]

Answer:

35,829,630 melodies

Step-by-step explanation:

There are 12 half-steps in an octave and therefore 12^7 arrangements of 7 notes if there were no stipulations.

Using complimentary counting, subtract the inadmissible arrangements from 12^7 to get the number of admissible arrangements.

\displaystyle \_\_ \:B_1\_\_ \:B_2\_\_ \:B_3\_\_ \:B_4\_\_ \:B_5\_\_

B_1 can be any note, giving us 12 options. Whatever note we choose, B_2, B_{...} must match it, yielding 12\cdot 1\cdot 1\cdot 1\cdot 1=12. For the remaining two white key notes, W_1 and W_2, we have 11 options for each (they can be anything but the note we chose for the black keys).

There are three possible arrangements of white key groups and black key groups that are inadmissible:

WWBBBBB\\WBBBBBW\\BBBBBWW

White key notes can be different, so a distinct arrangement of them will be considered a distinct melody. With 11 notes to choose from per white key, the number of ways to inadmissibly arrange the white keys is \displaystyle\frac{11\cdot 11}{2!}.

Therefore, the number of admissible arrangements is:

\displaystyle 12^7-3\left(\frac{12\cdot 11\cdot 11}{2!}\right)=\boxed{35,829,630}

6 0
2 years ago
Let f(x)=6/5x−1/2. Describe the transformations from the graph of f to the graphs of g(x)=−f(x) and h(x)=f(−x).
aivan3 [116]

Answer:

g(x)=-6/5x+1/2

h(x)=-6/5x-1/2

Step-by-step explanation:

1).   g(x)=−f(x) ?

f(x)=6/5x−1/2

g(x)=−(6/5x−1/2)

<u>g(x)=-6/5x+1/2</u>

2). h(x)=f(−x) ?

f(-x)=6/5(-x)−1/2

f(-x)=-6/5x-1/2

h(x)=-6/5x-1/2

8 0
3 years ago
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