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mamaluj [8]
2 years ago
14

Can you please help me??

Mathematics
1 answer:
Dominik [7]2 years ago
8 0

Answer: B

Step-by-step explanation: I know

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In the triangle shown below, what are the measures of angles A, B, and C? Round your answers to the nearest tenth of a degree. S
Naddik [55]

Answer:

The answer to your question is

A = 29.6°

B = 115.4°

C = 35°

Step-by-step explanation:

Process

1.- Use the Cosines law to answer this question

     c² = a² + b² - 2abcosФ

Solve for cos Ф

    cos Ф = (c² - a² - b² )/ -2ab

Substitution

    cosФ = (7² - 6² - 11²) / (-2)(6)(11)

    cosФ = (49 - 36 - 121) / -132

    cos Ф = -108 / -132

    cos Ф = 0.818

           Ф = 35° = C

Find B

   cos Ф = (b² - a² - c²)  / (-2ac)

   cos Ф = (11² - 6² - 7²)  / (-2)(6)(7)

   cos Ф = ( 121 - 36 - 49) / -84

  cos Ф = 36 / -84

  cos Ф = -0.429

         Ф = 115.4° = B

2.- Find a

The sum of the internal angles in a triangle equals 180°

     A + B + C = 180  

    A + 115.4 + 35 = 180

    A = 180 - 115.4 - 35

    A = 29.6°  

3 0
4 years ago
If a family of five spends, on the average, $125.75 on groceries each week how
lorasvet [3.4K]

Answer:

6036 $

Step-by-step explanation:

one month =4 weeks

12 months =12 ×4 =48 weeks

48 ×125,75 =6036 $

5 0
3 years ago
A. 1/5<br><br> B. 1/3<br><br> C. 7/15<br><br> D. 1/2
Allisa [31]

P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\ |\Omega|=15\cdot14=210\\ |A|=3\cdot14=42\\ |A \cap B|=3\cdot7=21\\\\ P(A)=\dfrac{42}{210}=\dfrac{7}{35}\\ P(A \cap B)=\dfrac{21}{210}=\dfrac{1}{10}\\\\ P(B|A)=\dfrac{\dfrac{1}{10}}{\dfrac{7}{35}}=\dfrac{1}{10}\cdot\dfrac{35}{7}=\dfrac{1}{2}\Rightarrow \text{D}

4 0
4 years ago
Please helppppp me i need it
valentinak56 [21]
Hey there!

Given rule is 2x-8

Given x = 8

On substituting ,

=> 2(8)-8

=> 16-8

=> 8

8 is the answer mate!

Hope it helps you

Please mark as brainliest.
5 0
3 years ago
Can someone please help and explain its due in a littleee
jek_recluse [69]

f(x) =  {x}^{2}  - 3x + 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (-1)

f( - 1) =  {( - 1)}^{2}  - 3 \times ( - 1) + 2  \\  \\   1  + 3 + 2  \\  \\   6.

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (z)

f(z) =  {z}^{2}  - 3 \times z + 2  \\  \\  {z}^{2}  - 3z + 2  \\  \\  {z}^{2} - 2z - z + 2 \\  \\ z(z - 2) - 1(z - 2) \\  \\ (z - 1)( z -2 ) \\  \\ (z - 1) = 0  \:  \: , \:  \: (z - 2) = 0\\  \\ z =  1 \:,  \: 2

<h2>••••••••••••••••••••••••••••••••••••••••</h2>

put x = (x+1)

f(x + 1)  = {x}^{2}  -  3x + 2 \\  \\  {(x + 1)}^{2}  - 3 (x + 1) + 2 \\  \\  {x}^{2}  + 1 + 2x - 3x - 3 + 2 \\  \\  {x}^{2}  - x \\  \\ x(x - 1) \\  \\ x(x - 1) = 0   \\  \\  x - 1 =  \frac{0}{x}  \\  \\ x - 1 = 0 \\  \\ x = 1.

<h2>•••••••••••••••••••••••••••••••••</h2>

put x = (√2 + 1 )

f( \sqrt{2}  + 1) =  {x}^{2}  - 3x + 2 \\  \\  {( \sqrt{2} + 1) }^{2}  - 3( \sqrt{2}  + 1) + 2 \\  \\ 2 + 1 +  2\sqrt{2}  - 3 \sqrt{2}  - 3 + 2 \\  \\ 3 - 1 \sqrt{2}  - 1 \\  \\ 2 -  \sqrt{2}  \\   \\  2 - 1.4 (optional \:  \:  \: steps)\\  \\ 0.6 \:  \:

4 0
2 years ago
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