What is the solution to the system of equations ? Y=2/3 x + 3 X= - 2

Mathematics

1 answer:

Firdavs [7]3 years ago

7 0

Answer:

x = -2, y = 5/3

Step-by-step explanation:

we have the value of x already (-2).

x=-2

Plug it into the first equation y = 2/3x+3

y = 2/3(-2)+3

y = -4/3+3

y = -4/3+9/3

y = 5/3

x = -2, y = 5/3

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Find the area of a triangle with a base length of 3 units and a height of 4 units. 3 square units 6 square units 7 square units

yan [13]

For this case we have that by definition, the area of a triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It is the base of the triangle

h: It is the height of the triangle

According to the data of the statement we have:

$b = 3 \ units\\h = 4 \ units$

Substituting in the formula we have:

$A = \frac {3 * 4} {2} = \frac {12} {2} = 6 \ units ^ 2$

So, the area of the triangle is $6 \ units ^ 2$

Answer:

$6 \ units ^ 2$

8 0

3 years ago

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If sin theta = 2/3, which of the following are possible

Ira Lisetskai [31]

Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø

to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2

Manipulating the equation to find the adjacent value = ?

adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)

so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b