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3 years ago

Link between mass and force of gravity?

2 answers:

8 0

Mass x Force of gravity = Weight

Weight is a force.

On Earth, the force due to gravity is ~9.81 N/Kg. So an object of 100 Kg will have a weight of ~981 N

eduard3 years ago

3 0

Force of gravity is what we call "weight".

It's the product of (mass) x (acceleration due to gravity).

On Earth, acceleration due to gravity is about 9.81 meters per second-squared.
It's different in other places. Example: It's about 1.62 on the Moon.

So the weight of any mass on Earth is (9.81) x (the mass), in Newtons.
The weight of the SAME mass on the Moon is (1.62) x (the mass), in Newtons.

You might be interested in

The fundamental frequency of a guitar string is 367 hz . part a what is the fundamental frequency if the tension in the string i

ANTONII [103]

The fundamental frequency of a string is given by:
$f_1 = \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where L is the string's length, T the tension and $\mu$ the linear density of the string.

We can see that f1 is proportional to the square root of T: $\sqrt{T}$ .
This means that if the new tension is half the initial value, the new fundamental frequency will be proportional to $\sqrt{ \frac{T}{2} }= \frac{ \sqrt{T} }{ \sqrt{2} }= \frac{f_1}{ \sqrt{2} }$

So, the new fundamental frequency will be
$f_1 ' = \frac{367 Hz}{ \sqrt{2} }=259.5 Hz$

6 0

4 years ago

Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional

Alexxx [7]

Answer:

165.529454

Explanation:

According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.

7 0

3 years ago

Will binoculars work properly if their prisms (assume n = 1.50) are immersed in water (nwater= 1.33)? assume that binoculars wor

Amanda [17]

The binoculars will not work properly.

Please refer to the diagram attached.

Binoculars work on the principle of total internal reflection. The incident ray from air enters the prism through on face normally and it strikes the opposite face at an angle of 45°. The ray undergoes Total internal reflection if its critical angle is less than the angle of incidence,which , in this case is 45°.

The critical angle $i_{c}$ is related to the refractive index of the material of glass μ as shown below.

$\mu =\frac{1}{sini_c}$

For a refractive index equal to 1.5, the critical angle is found as shown below.

$sini_c=\frac{1}{\mu} \\ =\frac{1}{1.5} \\ =0.666$

Take the inverse of the value 0.666 to determine the critical angle.

$sin^{-1} (0.666)=41.8^o$

The critical angle in air is less than the angle of incidence, and hence total internal reflection occurs in air.

When the binoculars are immersed in water, the ray passes into the glass through water. therefore, the refractive index of the prism when immersed in water is given by,

$\mu_g_w=\frac{\mu_g}{\mu_w}$

Therefore the critical angle c in this case is given by,

$sinc=\frac{\mu_w}{\mu_g}$

Substitute 1.33 for $\mu_w$ and 1.5 for $\mu_g$ .

$sinc=\frac{\mu_w}{\mu_g} \\ =\frac{1.33}{1.5} \\ =0.8866$

Take the inverse of the value 0.8866.

$c=sin^{-1} (0.8866)\\ =62^o$

Since the critical angle of the prism when immersed in water, is 62°, which is greater than the angle of incidence of 45° required for viewing the object, the binoculars which are set for Total reflection in air, will not function when immersed in water.