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3 years ago

Link between mass and force of gravity?

2 answers:

8 0

Mass x Force of gravity = Weight

Weight is a force.

On Earth, the force due to gravity is ~9.81 N/Kg. So an object of 100 Kg will have a weight of ~981 N

eduard3 years ago

3 0

Force of gravity is what we call "weight".

It's the product of (mass) x (acceleration due to gravity).

On Earth, acceleration due to gravity is about 9.81 meters per second-squared.
It's different in other places. Example: It's about 1.62 on the Moon.

So the weight of any mass on Earth is (9.81) x (the mass), in Newtons.
The weight of the <u>SAME mass</u> on the Moon is (1.62) x (the mass), in Newtons.

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26. An ice-skater who weighs 200 N is gliding across the ice. If the force of friction is 4 N. what is the

Scrat [10]

Answer:

0.02

Explanation:

coefficient of kinetic friction = μ

force of friction = Ff

Normal Force = FN, but

FN = -W

Ff = -μFN

so μ = Ff/FN

= 4N/200N

= 0.02.

7 0

3 years ago

A ball on a frictionless plane is swung around in a circle at constant speed. The acceleration points in the same direction as t

Kitty [74]

I believe it is False, only because the plane is Frictionless. Hope this helps, good luck.

4 0

3 years ago

Read 2 more answers

The discovery of which particle proved that the atom is not indivisible?

Blababa [14]

Maybe cuz your fat fat biches

8 0

3 years ago

The turntable in a microwave oven has a moment of inertia of 0.039 kg⋅m2 and is rotating once every 4.4 s . Part A What is its k

gayaneshka [121]

To solve this problem it is necessary to apply the concepts related to Kinetic Energy, specifically, since it is a body with angular movement, the kinetic rotational energy. Recall that kinetic energy is defined as the work necessary to accelerate a body of a given mass from rest to the indicated speed.

Mathematically it can be expressed as,

$KE = \frac{1}{2} I\omega^2$

Where

I = Moment of Inertia

$\omega =$ Angular velocity

Our values are given as

$I = 0.039kg\cdot m^2$

A revolution is made every 4.4 seconds.

$\theta = 1 rev \rightarrow 4.4s$

$\Rightarrow \omega = \frac{1rev}{4.4s}$

If the angular velocity is equivalent to the displacement over the time it takes to perform it then

$\omega = 0.2272rev/s(\frac{2\pi rad}{1rev})$

$\omega = 1.42rad/s$

Replacing at our previous equation we have,

$KE = \frac{1}{2} I\omega^2$

$KE = \frac{1}{2} (0.039)(1.42)^2$

$KE = 0.03993J$

Therefore the kinetic energy is equal to $3.9*10^{-2}J$

6 0

3 years ago

A 24 kg child slides down a 3.3-m-high playground slide. She starts from rest, and her speed at the bottom is 3.0 m/s.a. What en

Gelneren [198K]

Answer:

(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

(b) $U=668.16\ J$

Explanation:

Given:

mass of the child, $m=24\ kg$

height of the slide, $h=3.3\ m$

initial velocity of the child at the slide, $v_i=0 m.s^{-1}$

final velocity of the child at the bottom of slide, $v_f=3\ m.s^{-1}$

(a)

∴The initial potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

Initial potential energy:

$PE=m.g.h$