Static equilibrium.
Static equilibrium is a kind of equilibrium which occurs when an object is at rest.
Hope this helps!
Explanation:
It is given that,
The total mass of the wagon, rider and the rock is 99 kg
The mass of the rock is 0.261 kg.
The initial speed of the wagon, u = 0.519 m/s
Speed of the rock, u' = 15.9 m/s
(a) Let v is the speed of the wagon after the rock is thrown directly in forward direction.
The momentum will remain constant. Using the conservation of momentum as :
v = 0.22 m/s
(b) Let v' is the speed of the wagon after the rock is thrown directly in opposite direction, u' = -15.9 m/s
v' = 0.304 m/s
Hence, this is the required solution.
Answer:
<u>7.2 m</u>
Explanation:
In this scenario, the man possesses kinetic energy as he is in motion.
⇒ KE = 1/2mv²
His potential energy will be equal to the kinetic energy as per the law of conservation of energy.
So, 1/2mv² = mgh [potential energy]
⇒ v²/2 = gh
⇒ h = v²/2g
⇒ h = (12)²/2(10)
⇒ h = 144/20
⇒ h = <u>7.2 m</u>
Answer:
Explanation:
Work is given by the equation . Plugging in given values, we get:
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