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ladessa [460]
3 years ago
12

on a recent adventure trip, Anita Break went rock climbing. Anita was able to perform 1370 J of work in 100 seconds. Determine A

nita's power rating during this portion of the climb
Physics
1 answer:
Zanzabum3 years ago
5 0

        Power = (energy) / (time)

         =    (1370 joules) / (100 seconds)

         =       13.7  joules/second

         =       13.7 watts .

That's not an awful lot of power, especially for a strenuous activity like
rock-climbing.  Shoot !  Even I could probably perform at that level.

Compare 13.7 watts to the light power coming out of a 20-watt night light.

         13.7 watts  =  0.018 horsepower.      (rounded)
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True or false if the temperature does not change but the mass of the object increases the thermal energy in the object decreases
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Answer: im pretty sure its true

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You are working with a team to design a better electron microscope. To precisely control the beam of electrons, your team decide
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Answer and Explanation:

(a) The attached image below shows the diagram of a CRT in the helmholtz coils and well labelled with details

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r = \frac{mV}{qB}

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2 years ago
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Whiat is quantum numbers describes the size and energy of an orbital?
Levart [38]

Answer:

The answer is the principal Quantum number (n)

Explanation:

The principal quantum number is one of the four quantum numbers associated with an atom.

It is denoted by a number n=1,2,3,4 etc

It tells both size (directly) and energy (indirectly) of an orbital.

When n=1 means it is the closest to the nucleus and is the smallest orbital and with increase in principal quantum number, it depicts that size of the orbital is increasing.

It tells the energy of the orbital as well as smaller number means less distance from nucleus and having less energy. Since electrons requires to absorb energy to jump into higher orbitals making n=2,3,4 etc. Thus electrons in the orbitals with higher n number indicates higher energy orbitals.

7 0
3 years ago
A small bug walks up a wall 2 m. The bug then walks 2 m down the wall. What is the distance?
gizmo_the_mogwai [7]
4m. The big travels 2m twice
5 0
2 years ago
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Calculate, for the judge, how fast you were going in miles per hour when you ran the red light because it appeared Doppler-shift
sammy [17]

Answer:

The doppler effect equation is:

f' = \frac{v +v0}{v - vs}*f

In the equation we have frequencies, but then we have the wavelengths of the lights, remember the relation:

v = f*λ

then:

f = v/λ

and v is the speed of light, then:

f = c/λ

where:

f' is the observed frequency, in this case, is equal to f = (3*10^17nm/s)/550 nm

f is the real frequency, in this case, is (3*10^17nm/s)/650 nm

vs is the speed of the source, in this case, the source is not moving, then vs = 0 m/s.

v is the speed of the wave, in this case, is equal to the speed of light, v = 3*10^8 m/s

v0 is your speed, this is what we want to find.

Replacing those quantities in the equation, we get:

(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm

(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)

1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)

1.182*(3*10^8 m/s) -  (3*10^8 m/s) = v0 = 54,600,000 m/s

So your speed was 54,600,000 m/s, which is a lot.

6 0
3 years ago
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