Which change indicates that the universe is expanding?
2 answers:
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Refer to the diagram shown below.
The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.
By definition,
Work = Force x Distance.
(a) The work done by the girl is
W₁ = (17 N)*(3.5 m) = 59.5 J
(b) The work done by the boy is
W₂ = (13 N)*(-3.5 m) = - 45.5 J
(c) The work done by the net force is
W₃ = (4 N)*(3.5 m) = 14 J
Note that W₃ = W₁ + W₂
Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J
The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.
By definition,
Work = Force x Distance.
(a) The work done by the girl is
W₁ = (17 N)*(3.5 m) = 59.5 J
(b) The work done by the boy is
W₂ = (13 N)*(-3.5 m) = - 45.5 J
(c) The work done by the net force is
W₃ = (4 N)*(3.5 m) = 14 J
Note that W₃ = W₁ + W₂
Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J
Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation () to find v final, or the v to the left of the equal sign. We know
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of and do the same to the right side of the equation. Therefore, we can find v final with:
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get:
The final answer is 236.057 m/s.