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3 years ago

5

How many drive cycles can be completed with a initially fully charged battery?

1 answer:

IRINA_888 [86]3 years ago

5 0

Answer:

600 cycles

A phone battery is typically designed to last around 500 to 600 cycles, and a cycle is defined as charging a completely dead battery to 100% then draining it to zero again.

Explanation:

I hope it can help

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The fastest crossing of the Atlantic Ocean by an ocean

IgorLugansk [536]

That’s insane!!23456

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2 years ago

Titan is the only moon in the solar system with a significant atmosphere. which planet does titan orbit?

sveticcg [70]

"Saturn". It is largest moon of Saturn.

In short, Your Answer would be Option B

Hope this helps!

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3 years ago

See the person on the right side of the front car. Six reference points could be used to show that the person is in / is NOT in

Rasek [7]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

1. According to person standing on ground ~

The person is in motion

2. According to The car ~

The person is not in motion

3. According to the Seat ~

The person is not in motion

4. According to another person on ride ~

The person is not in motion

5. According to the track ~

The person is in motion

6. According to the Sun ~

The person is in motion

I hope that's what you were looking for, goodluck for your assignment ~

7 0

2 years ago

The density of gasoline is 730 kg/m3 at 0°C. Its average coefficient of volume expansion is 9.60 10-4(°C)−1. Assume 1.00 gal of

kipiarov [429]

Answer: 0.4911 kg

Explanation:

We have the following data:

$\rho_{0\°C}= 730 kg/m^{3}$ is the density of gasoline at $0\°C$

$\beta=9.60(10)^{-4} \°C^{-1}$ is the average coefficient of volume expansion

We need to find the extra kilograms of gasoline.

So, firstly we need to transform the volume of gasoline from gallons to $m^{3}$ :

$V=8.50 gal \frac{0.00380 m^{3}}{1 gal}=0.0323 m^{3}$ (1)

Knowing density is given by: $\rho=\frac{m}{V}$ , we can find the mass $m_{1}$ of 8.50 gallons:

$m_{1}=\rho_{0\°C}V$

$m_{1}=(730 kg/m^{3})(0.0323 m^{3})=23.579 kg$ (2)

Now, we have to calculate the factor $f$ by which the volume of gasoline is increased with the temperature, which is given by:

$f=(1+\beta(T_{f}-T_{o}))$ (3)

Where $T_{o}=0\°C$ is the initial temperature and $T_{f}=21.7\°C$ is the final temperature.

$f=(1+9.60(10)^{-4} \°C^{-1}(21.7\°C-0\°C))$ (4)

$f=1.020832$ (5)

With this, we can calculate the density of gasoline at $21.7\°C$ :

$\rho_{21.7\°C}=730 kg/m^{3} f=(730 kg/m^{3})(1.020832)$

$\rho_{21.7\°C}=745.207 kg/m^{3}$ (6)

Now we can calculate the mass of gasoline at this temperature:

$m_{2}=\rho_{21.7\°C}V$ (7)

$m_{2}=(745.207 kg/m^{3})(0.0323 m^{3})$ (8)

$m_{2}=24.070 kg$ (9)

And finally calculate the mass difference $\Delta m$ :

$\Delta m=m_{2}-m_{1}=24.070 kg-23.579 kg$ (10)

$\Delta m=0.4911 kg$ (11) This is the extra mass of gasoline

6 0

4 years ago

To measure specific heat, the student flows air with a velocity of 20 m/s and a temperature of 25C perpendicular to the length

san4es73 [151]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

3 0

3 years ago