How many drive cycles can be completed with a initially fully charged battery?

1. An electrically charged atom ___________

dmitriy555 [2]

Answer:

Is called an Ion

Explanation:

7 0

2 years ago

Read 2 more answers

Uranium-235 Fission

ExtremeBDS [4]

In the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation

<h3>Balanced nuclear reaction of Uranium</h3>

The balanced nuclear reaction of uranium is determined as follows;

$^{235}_{92}U\ --- > \ ^4_2He\ + \ ^{231}_{90}Th\ + \ energy$

Thus, in the balanced nuclear reaction of uranium 235, we have thorium 231, helium atom and energy released at the right of the equation while uranium 235 is on the left hand side of the nuclear reaction equation.

Learn more about nuclear reaction here:

brainly.com/question/25387647

#SPJ1

4 0

3 years ago

An apple is thrown across the cafeteria with a force of 10 N and at an acceleration of 6 m/s2. What is the mass of the apple? ..

Komok [63]

Answer:

Explanation:

F = m * a

The apple's acceleration is not influenced by the acceleration due to gravity for this question. In real life it most certainly is influenced by gravity.

F = m * a

F = 10 Newtons.

a = 6 m/s^2

m = 10/6 = 1.66 kg. Mighty large apple

7 0

4 years ago

A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches

yaroslaw [1]

Answer:

(a) The parachutist spent 24.84 secs in air

(b) The height the fall begins is 472 m

Explanation:

Here is the complete question:

A parachutist bails out and freely falls 63 m. Then the parachute opens, and thereafter she decelerates at 1.5 m/s2. She reaches the ground with a speed of 3.3 m/s. (a) How long is the parachutist in the air (b) At what height does the fall begin?

Explanation:

From one of the equations of kinematics for free fall

$H = ut - \frac{1}{2}gt^{2}$

Where H is the height

u is the initial velocity

t is the time

and g is the acceleration due to gravity (Take g = 9.8 m/s2)

Now, we can find the time spent before the parachute opens.

u = 0 m/s (we assume the parachutist starts from rest)

H = - 63 m

∴ $-63 = 0(t) - \frac{1}{2}(0.98) t^{2} \\-63 = -4.9 t\\t^{2} = \frac{63}{4.9} \\t^{2} = 12.86\\t = \sqrt{12.86} \\t = 3.59 s$

This the time spent before the parachute opens

Also from one of the equations of kinematics for free fall

$v = u - gt$

where v is the final velocity

We can determine the final velocity before the parachute opens and she starts to decelerate

∴ $v = - 9.8(3.59)\\v = - 35.18m/s$

Now, we will calculate the time spent after the parachute opens

From one of the equation of kinematics for linear motion,

$v = u + at$

Here, the initial velocity will be the final velocity just before the parachute opens, that is

$u = - 35.18 m/s$

From the question,

$v = - 3.3 m/s$

$a = 1.5 m/s^{2}$

We then get

$-3.3 = - 35.18 + (1.5)t$

$-3.3 + 35.18 = 1.5t\\31.88 = 1.5t$

$t = \frac{31.88}{1.5}$

$t = 21.25 secs$

(a) To determine how long the parachutist is in the air,

That is sum of the time used when falling freely and the time used after the parachute opens

= 3.59 secs + 21.25 secs

24.84 secs

Hence, the parachutist spent 24.84 secs in air

(b) To determine what height the fall begins

First, we will calculate the height from which the parachute opens

From one of the equation of kinematics for linear motion,

$x = ut + \frac{1}{2}at^{2} \\$

$x = -35.18(21.25) + \frac{1}{2}(1.5)(21.25)^{2} \\x = -747.58 + 338.67\\x = -408.91m\\$

$x$ ≅ $- 409m$

Hence, the height the fall begins is 63m + 409m

= 472 m

3 0

3 years ago

What is the frequency of a wave with speed 3m/s and wavelength 6m?

Korolek [52]

The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1

3 0

2 years ago