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3 years ago

10

Please help!! Look at pic

1 answer:

kkurt [141]3 years ago

7 0

Answer:

Explanation:

Voltage and Current relation is given by V=IR
I=9A

R=4Ohm

V=IR
V=9x4=36Volts

Resistance = 4 Ohm

Current = 9 Ampere

Voltage = 36 Volts

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A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an

Nadya [2.5K]

Initial volume of mercury is
V = 0.1 cm³

The temperature rise is 35 - 5 = 30 ⁰C = 30 ⁰K.

Because the coefficient of volume expansion is 1.8x10⁻⁴ 1/K, the change in volume of the mercury is
ΔV = (1.8x10⁻⁴ 1/K)*(30 ⁰K)(0.1 cm³) = 5.4x10⁻⁴ cm³

The cross sectional area of the tube is
A = 0.012 mm² = (0.012x10⁻² cm²).
Therefore the rise of mercury in the tube is
h = ΔV/A
= (5.4x10⁻⁴ cm³)/(0.012x10⁻² cm²)
= 4.5 cm

Answer: 4.5 cm

7 0

4 years ago

Read 2 more answers

A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.

ValentinkaMS [17]

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

$v = 1.74 x 10^{3} ( \frac{m}{s} )$

$\alpha = 58$ °

$v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )$

$v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)$

$v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\$

$t= \frac{2*v_{y} }{g}$

$t= \frac{2*1475.603 }{9.8}$

$t= 301.143 s$

$v= \frac{s}{t} \\s= v_{x}*t$

$s= 922.059 \frac{m}{s} * 301.143 s$

$s = 277671.77 m$

4 0

4 years ago

A wave has frequency of 5 Hz and a speed of 25 m/s. What is the wavelength of the wave?

Artyom0805 [142]

Answer:

This is the answer that I got.

Explanation:

Just check over it once.

5 0

2 years ago

Please help. I don’t understand

Irina18 [472]

The answer to your thing is d

6 0

3 years ago

A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.90 kg box that is sitting on the horizontal,

Lady_Fox [76]

Answer:

6.875 m/s

Explanation:

The force is variable which is given by

F(x) = 18 - 0.53 x

mass of the box, m = 8.9 kg

initially it is at rest at x = 0

Let the velocity is v after travelling a distance of 15 m.

According to the work energy theorem, the work done by all the forces is equal to the change in kinetic energy of the body.

Work done = change in kinetic energy

$\int \overrightarrow{F}.d\overrightarrow{x}=\Delta K.E$

$\int_{0}^{15} \left ( 18-0.53 x \right )dx=\frac{1}{2}\times m \left ( v^{2}-u^{2} \right )$

$\left ( 18x-0.265x^{2} \right )_{0}^{15}=\frac{1}{2}\times 8.9\times \left ( v^{2}-0^{2} \right )$

18 x 15 - 0.265 x 15 x 15 = 4.45 x v²

270 - 59.625 = 4.45 v²

v² = 47.275

v = 6.875 m/s

Thus, the final velocity of the box is 6.875 m/s.

4 0

3 years ago