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Dmitry_Shevchenko [17]
3 years ago
5

Please help. I don’t understand

Physics
1 answer:
Irina18 [472]3 years ago
6 0
The answer to your thing is d
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If  64  is term #1 of the sequence,
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                                      <em> T(n) = 50 + 14n </em>.


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"If E = 7.50V and r=0.45Ω, find the minimum value of the voltmeter resistance RV for which the voltmeter reading is within 1.0%
Virty [35]

Answer:

The  minimum value is R_V =44.552\  \Omega

Explanation:

From the question we are given that

                  The voltage is E = 7.5V

                  The internal  resistance is r = 0.45

The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery

  What is means is that we need to obtain voltmeter resistance such that

                                V = (100% -1%) of E

Where E  is the  e.m.f of the battery and V is the voltmeter reading

                          i.e    V = 99% of E = 0.99 E = 7.425  

Generally

                E = V + ir

     where ir is the internal potential difference of the voltmeter and

                V is the voltmeter reading

 Making i the subject of the formula above

            i = \frac{(E-V)}{r}

               =\frac{7.50-7.425}{0.45}

              = 0.1667 A

Now the current is constant through out the circuit so,

                  V = iR_V

Where  R_V is the value of voltmeter resistance

                Hence R_V = \frac{V}{i}  = \frac{7.425}{0.1667}

                                  =44.552\  \Omega

                       

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