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3 years ago

A shell is fired from the ground with an initial speed of 1.74 ✕ 103 m/s at an initial angle of 58° to the horizontal.

Physics

1 answer:

ValentinkaMS [17]3 years ago

4 0

Answer:

a) horizontal range s=277671.77 m

b) time the shell is in motion 301.143 s

Explanation:

Is a parabolic movement so the velocity have two components:

$v = 1.74 x 10^{3} ( \frac{m}{s} )$

$\alpha = 58$ °

$v_{y} =v*Sen (\alpha )\\v_{x} =v*Cos (\alpha )$

$v_{y} =1740*Sen (58 )\\v_{x} =1740*Cos (58)$

$v_{y} = 1475.603 \frac{m}{s}\\v_{x} = 922.059 \frac{m}{s}\\$

$t= \frac{2*v_{y} }{g}$

$t= \frac{2*1475.603 }{9.8}$

$t= 301.143 s$

$v= \frac{s}{t} \\s= v_{x}*t$

$s= 922.059 \frac{m}{s} * 301.143 s$

$s = 277671.77 m$

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Making dt the subject of formula, we have;

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Answer:

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where

f: frequency of the source = ?

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vo: speed of the observer = 40.0 m/s

vs: speed of the source = 0 m/s (stationary)

You replace the values of all parameters in the equation (1):

To calculate f' you first calculate the frequency of the sound wave, by using the following formula:

$v=\lambda f\\\\$

v: speed of sound

λ: wavelength = 0.700 m

$f=\frac{v}{\lambda}=\frac{343m/s}{0.700m}=480Hz$

Next, you replace the values of all parameters in the equation (1):

$f'=(490Hz)(\frac{343m/s-40.0m/s}{343m/s})=432Hz$

hence, the frequency perceived by the car is 432 Hz

b) To calculate the power of the sound wave, when the car is 70.0 maway from the speaker, you use the following formula:

$I=\frac{P}{4\pi r^2}$

P: power of the source = 50.0 W

r: distance to the source = 70.0 m

$I=\frac{50.0 W}{4\pi(70.0m)^2}=8.12*10^{-4}\frac{W}{m^2}$

hence, the intensity is 8.12*10^⁻4 W/m^2

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3 years ago

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