Answer:

Step-by-step explanation:
Given expression:



Replace 900 with 30² :




(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).


Simplify:

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).
Answer:
21 1/3
Step-by-step explanation:
20 ÷ 15/16=
20/1 ÷ 15/16=
20/1*16/15=
4/1*16/3=
64/3=
21 1/3
Answer:
C. 540 in^3
Step-by-step explanation:
What you do is you use the formula V=lwh.
All your doing id=s multiplying them together.
V=18*10*3=540 in^3.
9x - 4(x - 2) =x + 20
We move all terms to the left:
- 9x -4(x - 2) - (x + 20) = 0
Multiply
- 9x - 4x -(x + 20) + 8 = 0
We get rid of the parentheses.
We add all the numbers and all the variables.
We move all terms containing x to the left hand side, all other terms to the right hand side
Answer:
The photo below
Step-by-step explanation:
I hope I've helped you.
I hope you've undertand the image.