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Zarrin [17]
2 years ago
15

Two cats are sitting on a 30 m hill. One cat

Physics
1 answer:
V125BC [204]2 years ago
3 0

Answer:

Cat with 6 kg sitting on a 30 meter hill has greater potential energy.

Explanation:

gravitational potential energy (J) = mass (kg) × gravitational field × height (m)

<h3 /><h3><u>Note</u>:</h3>

gravitational field in Earth is 10 N/kg = <u>fixed unit</u>

<h3 /><h3><u>Given</u>:</h3>

1st Cat: 4 kg

2nd Cat: 6 kg

Both of their height is 30 meters.

<h3><u>Solve for g.p.e</u>:</h3>

1st cat = mgh = 4 × 10 × 30 = 1200 Joules

2nd cat = mgh = 6 × 10 × 30 = 1800 Joules

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A woman can row a boat at 5.60 km/h in still water. (a) If she is crossing a river where the current is 2.80 km/h, in what direc
katrin2010 [14]

Answer:

a) θ=210°, b) t=1.155hr, c) t=1.333hr, d) t=1.333hr, e) θ=180° (straight across), f) t=1hr.

Explanation:

So, the very first thing we nee to do when solving this problem is draw a diagram that represents it. In the attached picture I show a diagram for each part of this problem.

part a)

So, for her to move in a direction directly opposite her starting point, the x-component of her velocity must be de same as the velocity of the river in the opposite direction. We can use this fact to find the angle we need. If we analize the triangle I drew in the diagram, we can ses that:

cos \theta = \frac {V_{river}}{V_{boat}}

When solving for theta, we get that:

\theta =cos^{-1} ( \frac {V_{river}}{V_{boat}})

so now we can substitute the corresponding values:

\theta =cos^{-1} ( \frac {2.80km/hr}{5.60km/hr}})

Which yields:

\theta = 60^{o}

but we are measuring the angle relative to the line perpendicular to the river, positive if down the river. So we need to subtract the angle from 270° so we get:

θ=270°-60°=210°

part b)

for part b, we need to find what the y-component for the velocity of the boat is for an angle of 210° as shown in the problem, so we get that:

V_{y}=5.60km/hr*cos(210^{o})

V_{y}=-4.85km/hr

The woman will head in a negative 5.60km distance from one side to the other, so we get that the time it takes her to go to the other side of the river is:

t=\frac{y}{V_{y}}

t=\frac{5.60km}{4.85km/hr}=1.155hr

part c)

In order to find the time it takes her to travel 2.80km down and up the river, we need to find the velocities she will have in both directions. First, down stream:

V_{ds}=V_{river}+V{boat}

V_{ds}=2.80km/hr+5.60km/hr=8.40km/hr

and now up stream:

V_{us}=V_{boat}-V{river}

V_{us}=5.60km/hr-2.80km/hr=2.80km/hr

Once we got these two velocities we will now need to find the time to take each trip:

time down stream:

t_{ds}=\frac{x}{v_{ds}}

t_{ds}=\frac{2.80km}{8.40km/hr}=0.333hr

and the time up stream:

t_{us}=\frac{x}{v_{us}}

t_{us}=\frac{2.80km}{2,80km/hr}=1hr

so the total time will be:

t_{ds}+t_{us}=0.333hr+1hr=1.333hr

d) the time it takes the boat to go upstream and then downstream for the same distance is the same as the time we got on part c, since both times will be the same but they will come in different order, but their sum will be just the same:

t=1.333hr

e) For her to cross the river faster, she must row in a 180° direction (this is in a direction straight accross the river) that way she will use all her velocity to move across the river. (Even though she will move a certain distance horizontally and will not reach a point opposite to the starting point.)

f) In order to find the time it takes her to get to the other side, we need to divide the distance into the velocity of the boat.

t=\frac{d}{v_{boat}}

t=\frac{5.60km}{5.60km/hr}

so

t= 1hr

4 0
4 years ago
Read 2 more answers
A pickup truck has a width of 79.0 in. If it is traveling north at 42 m/s through a magnetic field with vertical component of
bekas [8.4K]

Answer:

The magnitude of the induced Emf is 0.003371V

Explanation:

The width of the truck is given as 79inch but we need to convert to meter for consistency, then

The width= 79inch × 0.0254=2.0066 metres.

Now we can calculate the induced Emf using expresion below;

Then the induced EMF= B L v

Where B= magnetic field component

L= width

V= velocity

=(40*10^-6) × (42) × (2.0066)

=0.003371V

Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V

8 0
4 years ago
How are volume and decibels related
Yanka [14]

Answer:

The more energy a sound has the louder we perceive it

Explanation:

To measure volume we use the unit of decibels – abbreviated to dB. The lowest perceivable volume, meaning the quietest sound humans can hear, is 0 decibels. ... Thus, 60 dB are perceived as twice as loud as 50 dB

5 0
3 years ago
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Plz help to answer the sheet above thanks
AysviL [449]

Answer:

(B) sound/kinetic

(E) Gravitational/kinetic

(F) mechanical/sound

Explanation:

(B) the useful energy transfer is sound but a by product of that is kinetic or mechanical energy because of the vibrations needed to make sound

(E) the useful energy transfer is Gravitational potential but a by product of that is kinetic or mechanical energy

(F) the useful energy transfer is kinetic or mechanical energy but the byproduct is noise and occasionally heat

6 0
3 years ago
How much power is necessary to do 50 J of work in 5 seconds
Alex73 [517]
Power = Work / Time

If W = 50 J and T = 5s

P = W/T = 50J/5s = 10 Watts
7 0
4 years ago
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