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stich3 [128]
3 years ago
5

7. What is the acceleration of a 1,300 kg truck with a net force of 5,000 newtons (N)?

Physics
2 answers:
rusak2 [61]3 years ago
7 0

Force( net ) = mass × acceleration

5000 = 1300 × acceleration

acceleration = 5000 ÷ 1300

acceleration = 50/13

acceleration = 3.846 N/Kg

Crank3 years ago
5 0

Answer: 1200 kg

Explanation: Taking into account the Newton's second law, the mass of the vehicle is 1200 kg.

In first place, acceleration in a body occurs when a force acts on a body. There are two factors that influence the acceleration of an object: the net force acting on it and the mass of the body.

Newton's second law states that this force will change the speed of an object because the speed and / or direction will change. These changes in velocity are called acceleration.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

F = Force [N]

m = Mass [kg]

a = Acceleration [m/s²]

In this case, you know:

F= 1800 N

m= ?

a= 1.5 m/s²

Replacing:

1800 N= m× 1.5 m/s²

Solving:

m= 1800 N÷1.5 m/s²

m= 1200 kg

Finally, the mass of the vehicle is 1200 kg.

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7 0
3 years ago
A car has a force of 2000N and a mass of 1000kg. What is the acceleration
Anastaziya [24]

Answer:

2m/s/s

Explanation:

The formula goes- F=MA

F-Force M-Mass & A-Acceleration

We need to rearrange this formula to find the acceleration-

A=F/M

All we need to do now is substitute the values in

A=2000N/1000kg

A=2m/s^2

In the given option the last option (2m/s/s) would be the ans, as it's the same as 2m/s^2

So ya, I guess that's all

6 0
3 years ago
How should the student change the circuit to give negative values for current and
natulia [17]

Answer:

changing the polarity or direction of the battery changes the sign of the voltage and the current

Explanation:

The sign of current and voltage are due to established conventions.

The way that a DC circuit with negative current values ​​is by changing the polarity of the power source or by inverting the battery, this creates that the electrons move in the opposite direction

Changing the battery also changes the direction of the power difference, since the potential from positive to negative, in most cases negative is assigned a potential of zero volts

In summary, changing the polarity or direction of the battery changes the sign of the voltage and the current

3 0
3 years ago
Write this large number in scientific notation. Determine the values of Vm) and (n) when the following mass of the Earth is writ
hichkok12 [17]

Answer : The answer is, 5.97, 24

Explanation :

Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example :

5000 is written as 5.0\times 10^3

889.9 is written as 8.899\times 10^{-2}

In this examples, 5000 and 889.9 are written in the standard notation and 5.0\times 10^3  and 8.899\times 10^{-2}  are written in the scientific notation.

If the decimal is shifting to right side, the power of 10 is negative and if the decimal is shifting to left side, the power of 10 is positive.

As we are given the 5,970,000,000,000,000,000,000,000 in standard notation.

Now converting this into scientific notation, we get:

\Rightarrow 5,970,000,000,000,000,000,000,000=5.97\times 10^{24}

As, the decimal point is shifting to left side, thus the power of 10 is positive.

Hence, the answer is, 5.97\times 10^{24}

Now the answer is comparing to m.\times 10^n

So, m = 5.97 and n = 24

Thus, the answer is, 5.97, 24

5 0
3 years ago
An aluminum "12 gauge" wire has a diameter d of 0.205 centimeters. The resistivity ρ of aluminum is 2.75×10−8 ohm-meters. The el
Alborosie

Answer:

I = 4.75 A

Explanation:

To find the current in the wire you use the following relation:

J=\frac{E}{\rho}      (1)

E: electric field E(t)=0.0004t2−0.0001t+0.0004

ρ: resistivity of the material = 2.75×10−8 ohm-meters

J: current density

The current density is also given by:

J=\frac{I}{A}        (2)

I: current

A: cross area of the wire = π(d/2)^2

d: diameter of the wire = 0.205 cm = 0.00205 m

You replace the equation (2) into the equation (1), and you solve for the current I:

\frac{I}{A}=\frac{E(t)}{\rho}\\\\I(t)=\frac{AE(t)}{\rho}

Next, you replace for all variables:

I(t)=\frac{\pi (d/2)^2E(t)}{\rho}\\\\I(t)=\frac{\pi(0.00205m/2)^2(0.0004t^2-0.0001t+0.0004)}{2.75*10^{-8}\Omega.m}\\\\I(t)=4.75A

hence, the current in the wire is 4.75A

4 0
3 years ago
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