<h2>34.9×46×809</h2><h3>=1605.4×809 </h3><h3>=1298768.6</h3>
please mark this answer as brainlist
<span>net work = change in kinetic energy
for Block B, we just have the force from block A acting on it
F(ab)d= .5(1)vf² - .5(1)(2²)
F(ab)d= .5vf² - 2
Block A, we have the force from the hand going in one direction and the force of block B on A going the opposite direction
10-F(ba)d = .5(4)vf² - .5(4)(2²)
10-F(ba)d = 2vf² - 8
F(ba)d = 18 - 2vf²
now we have two equations:
F(ba)d = 18 - 2vf²
F(ab)d= .5vf² - 2
since the magnitude of F(ba) and F(ab) is the same, substitute and find vf (I already took into account the direction when solving for F(ab)
10-.5vf² + 2 = 2vf² - 8
12 - .5vf² = 2vf² - 8
20 = 2.5vf²
vf² = 8
they both will have the same velocity
KE of block A= .5(4)(2.828²) = 16 J
KE of block B=.5(1)(2.828²) = 4 J</span>
The first object also has half the inertia.
Answer: Option A
<u>Explanation:</u>
Inertia is the tendency of an object to remain in its state. It resists the change in the state of object due to any external forces. So the inertia is the property of an object to resists the change in its state due to any kind of external force. Thus as the mass decreases, the central mass of inertia of the object will also decrease as both are directly proportional to each other.
This should help,
Search up the Scientific method and lookup for the meaning of each word.
I can't help with all of it but this should help for most
The work done by the heat engine is 40 kCal.
The given parameters;
- input heat of the engine, Q₁ = 70 kCal
- output heat of the engine, Q₂ = 30 kCal
To find:
- the work done by the heat engine
The work done by the heat engine is the change in the heat energy of the engine;
W = Q₂ - Q₁
Substitute the given parameters and solve work done (W)
W = 70 kCal - 30 kal
W = 40 kCal
Thus, the work done by the heat engine is 40 kCal.
Learn more here: brainly.com/question/4280097
