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myrzilka [38]
3 years ago
10

What is the difference between displacement and distance travelled​

Physics
2 answers:
IrinaK [193]3 years ago
8 0
Displacement in Space
It is the length of a body's real route. It is the shortest distance between the body's final and beginning positions.
It's a number with a scalar value. It's a quantity with a vector.
It can't possibly be negative. It might be a negative number, a zero number, or a positive number.
Ierofanga [76]3 years ago
7 0

Answer:

displacement is the distance moved in stated direction.

displacement is the starting point to the end point.

distance is the distance travelled in unit of time.

distance is the whole journey

here is an example:

so what is the displacement?

like I said before displacement is the starting to the end point.

<em><u>so the displacement is 500km</u></em>

and the distance?

distance is the whole journey

<em><u>so it is 400+300=700km</u></em>

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A guitar string of length L = 0.79 m is oriented along the x-direction and under a tension of T = 74 N. The string is made of st
Orlov [11]

Answer:

74 N

Explanation:

T = Tension in the string = 74 N

\rho = Density of the steel = 7800 kg/m³

A = Area = \pi r^2

r = Radius = 8.5\times 10^{-4}\ m

Linear density is given by

\mu=\rho A\\\Rightarrow \mu=7800\times \pi (8.5\times 10^{-4})^2\\\Rightarrow \mu=0.0177\ kg/m

The linear density is 0.0177 kg/m

Velocity is given by

v=\sqrt{\dfrac{T}{\mu}}\\\Rightarrow v=\sqrt{\dfrac{74}{0.0177}}\\\Rightarrow v=64.65903\ m/s

The velocity of the wave on the guitar string is 64.65903 m/s

8 0
3 years ago
How can I solve this?<br><br>I managed to find Part A, but I got stuck trying to find Part B and C
maxonik [38]

Answer:

Parte B : 31.18º , Parte C: 31.17º

Explanation:

Parte B: The angle between the glass and the water before it enters the water is going to be equal to the value of the angle when it enters the glass , 27.13º.

Using the formula n1 senθ1 = n2 senθ2 , where n1=1.51 , θ1=27.13º, n2=1.33 , it gives us θ2=31.18º.

Parte C: n1= 1 , θ1=43.5º, n2=1.33

Using the same formula : n1 senθ1 = n2 senθ2 , it gives us θ2= 31.17º.

6 0
3 years ago
What is the net force needed to accelerate a 21.4 kg grocery sack upward at 1.5 m/s2?
marshall27 [118]

Answer:

32.1 N Please Give Brainliest

Explanation:

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How do creepers explode
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From you getting close to them

Explanation:

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6 0
3 years ago
Read 2 more answers
1. The strength coefficient and strain-hardening exponent of brass are 100,000 lb/in2 and 0.35 respectively. A cylindrical speci
aleksandr82 [10.1K]

To solve this problem we will apply the concepts of strain, flow stress and average flow stress to find the required data. We will start by calculating the Strain which is the logarithmic relationship between the longitudinal change. Later we will find the flow stress through the strength coefficient, the strain and the strain-hardening exponent. Finally with the found values it will be possible to find the average flow stress,

Now the strain is calculated with the logaritmic relation of the lengths.

\epsilon = ln(\frac{1.5}{3.0})

\epsilon = ln(0.5)

\epsilon = 0.69315in/in

With this value we can calculate the flow stress,

Y_f = K\epsilon^n

Here,

K = Strneght coefficient

n = Strainhardening exponent of brass

Y_f = (100000)(0.69315)^{0.35}

Y_f = 87961lb/in^2

Finally the average flow stress will be given under the relation:

\bar{Y_f} = \frac{K\epsilon^n}{1+n}

\bar{Y_f} = \frac{(100000)(0.69315)^{0.35}}{1.35}

\bar{Y_f} = 65156lb/in^2

6 0
3 years ago
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