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Ierofanga [76]
1 year ago
15

W

Physics
1 answer:
Alona [7]1 year ago
7 0

In the circuit, the total current is 60 A and the voltage is 240 V. If R1

resistance is 20 Ω, then the R2 resistance  would be 5 Ω

<h3>What is resistance?</h3>

Resistance is the obstruction of electrons in an electrically conducting material. The SI unit of the resistance is Ohm

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

where V is the voltage

I is the current

R is the resistance

For the given problem V= 240 V and I = 60 A

R = V/I

R =240/60

R =4 Ω

For calculating equivalent resistance in parallel combination.

1/Re = 1/R1  + 1/R2

1/4 = 1/20 +  1/R2

R2 = 5 Ω

Thus , the R2 resistance would be 5 Ω, therefore the correct answer is option B.

Learn more about resistance here

brainly.com/question/14547003

#SPJ1

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Answer:

Q = 6.33μC

Explanation:

To find the value of the charge Q you take into account both gravitational force and electric force over each ball. By symmetry you can use the fact that both balls experiences the same forces. Hence you only take into account the forces for one ball for the x component and y component:

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The electric force is given by:

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You divide both equation in order to eliminate the tension T:

tan\theta=\frac{F_e}{Mg}=k\frac{Q^2}{Mgr^2}

By doing Q the subject of the formula and replacing you obtain:

Q=\sqrt{\frac{tan\theta Mgr^2}{k}}=\sqrt{\frac{tan45\°(0.09kg)(2m)^2}{(8.89*10^{9}Nm^2/C^2)}}=6.33*10^{-6}C=6.33\mu C

hence, the charge of the balls is 6.33μC

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