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2 years ago

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Physics

1 answer:

Alona [7]2 years ago

7 0

In the circuit, the total current is 60 A and the voltage is 240 V. If R1

resistance is 20 Ω, then the R2 resistance would be 5 Ω

<h3>What is resistance?</h3>

Resistance is the obstruction of electrons in an electrically conducting material. The SI unit of the resistance is Ohm

The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law.

V=IR

where V is the voltage

I is the current

R is the resistance

For the given problem V= 240 V and I = 60 A

R = V/I

R =240/60

R =4 Ω

For calculating equivalent resistance in parallel combination.

1/Re = 1/R1 + 1/R2

1/4 = 1/20 + 1/R2

R2 = 5 Ω

Thus , the R2 resistance would be 5 Ω, therefore the correct answer is option B.

Learn more about resistance here

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DiKsa [7]

Answer:

The correct answer is "64 J".

Explanation:

The given values are:

Mass,

m = 52 kg

Velocity,

v = 6 m/s

Mechanical energy,

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Now,

The gravitational potential energy will be:

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3 years ago

g A loop circuit has a resistance of R1 and a current of 2 A. The current is reduced to 1.4 A when an additional 2.2 Ω resistor

Mrrafil [7]

Answer:

R1 = 5.13 Ω

Explanation:

From Ohm's law,

V = IR............... Equation 1

Where V = Voltage, I = current, R = resistance.

From the question,

I = 2 A, R = R1

Substitute into equation 1

V = 2R1................ Equation 2

When a resistance of 2.2Ω is added in series with R1,

assuming the voltage source remain constant

R = 2.2+R1, and I = 1.4 A

V = 1.4(2.2+R1)................. Equation 3

Substitute the value of V into equation 3

2R1 = 1.4(2.2+R1)

2R1 = 3.08+1.4R1

2R1-1.4R1 = 3.08

0.6R1 = 3.08

R1 = 3.08/0.6

R1 = 5.13 Ω

6 0

3 years ago

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3 years ago

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artcher [175]

Answer:

Explanation:

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3 years ago