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liberstina [14]

1 year ago

6

The price of a television in a certain store was a dollars in June. On the first day of each month after June, the price was red

uced by 20 percent of the price for the previous month. What was the price of the television during the month of Sep- tember?

1 answer:

Shtirlitz [24]1 year ago

6 0

Answer:

0.8

Step-by-step explanation:

multiply 1.00 .20 4 times

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Select all the correct answers.

Tanya [424]

Answer:

x=24

y=21

Step-by-step explanation:

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2 years ago

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Evaluate the expression,<br> if x = 9, y = 3, and z = 5.<br> z2 • (x-y)

Bad White [126]

$\huge\text{Hey there!}$

$\mathsf{z^2 \times (x - y)}$

$\mathsf{= 5^2 \times (9 - 3)}$

$\mathsf{= 5 \times 5 \times (9 - 3)}$

$\mathsf{= \bold{25}\times(9 - 3)}$

$\mathsf{= 25\times \bf 6}$

$\mathsf{= \bf 150}$

$\huge\text{Therefore, your answer should be: }$

$\huge\boxed{\frak{150}}\huge\checkmark$

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1 year ago

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Which parametric equations represent y = – |x|? Check all that apply.

Alenkasestr [34]

Answer:

The right options are C and E.

Step-by-step explanation:

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2 years ago

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I’ll give thanks and five star and brainliest

Luba_88 [7]

QUESTION:

When you factor a little perfect square trinomial, which pattern results?

ANSWER:

[2] The square of a binomial pattern.

EXPLANATION:

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8 0

2 years ago

Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

Therefore,

$\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)$

5 0

2 years ago