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frosja888 [35]
3 years ago
12

How do I solve 5x=-4y+4;x=1,2,3

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0
X=1
5=-4y+4
4y=-1
y=-1/4

x=2
10=-4y+4
4y=-6
y=-3/2

x=3
15=-4y+4
4y=-11
y=-11/4
OleMash [197]3 years ago
3 0

Answer:y_1 = -1/4\\y_2 = -3/2\\y_3 = -11/4

Step-by-step explanation:

We replace every x's on the equation

y =\frac{5x - 4}{-4}\\

For x = 1

y_1 = \frac{5*1 - 4}{-4} = -1/4

For x = 2

y_2 = \frac{5*2 - 4}{-4} = -6/4 = -3/2

For x = 3

y_3 = \frac{5*3 - 4}{-4} = -11/4

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34kurt
TQRS is an inscribed quadrilateral.
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It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.

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<h3>setup</h3>

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<h3>2.</h3>

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