Answer:
la respuesta esta abajo
Step-by-step explanation:
a) Sea x el número del artículo x mientras que y representa el número del artículo y.
Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:
2x + 5y ≤ 40
b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.
c) Para 10 unidades de X y 5 unidades de y:
2 (10) + 5 (5) = 45> 40
Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.
Answer:quasi experiment
Step-by-step explanation:
Because it is basically for comparison usually by measuring outcomes if a program by participants and non participants
Answer:
See below.
Step-by-step explanation:
1.) 5√6
2.) 6√2
3.) 3√7
To solve this without the use of a calculator, split the given number into a series of products (numbers multiplied) and look for pairs.
Look at the attached example of Problem 1 to get a better idea of what I mean.
Answer:
1024
Step-by-step explanation:
yeah it's 1024 lol
Answer:
The amplitude of the oscillation in this oscillating system, after reaching the steady-state, is 3.984.
Step-by-step explanation:
Assume you know a and b values, which you do not actually need to know to solve the question.
The given general solution of the equation is made up of three terms, namely:
- A constant value (equal to 4),
- a cosine term: 3.984cos(2nt-B)
- a cosine, exponential term: 2.81exp(-8.58t)cos(at + o)
This means that, after a certain time (for large values of time "t"), when the system reaches its <u>steady-state</u>, the following will happen to these parts, respectively:
- The constant value will remain as 4. It shall not cancel, but it shall not provide any oscillation either, and, in turn, no amplitude nor frequency.
- The second term will always be a cosine, since it is a periodic function. Its amplitud is "3.984" and its frequency is "2n" radians/second. Its phase is actually "B".
- This third term is not a periodic functon. It is made up of a periodic function multiplied by an exponential function, whose exponent is negative (for any positive value of time variable "t"). This exponential function approaches to zero when its exponent approaches to minus infinity. So, after a certain time -or, in other words, once the steady-state is eventually reached- the product will be a delimited function (cosine, whose absolute value is always than "1") multiplied by zero. That is, this third term, as a whole, approaches to zero for large, infinite values of time "t".
All in all, once the steady-state is reached, the solution shall remain as:
x = 4+ 3.984cos(2nt-B).
The only oscillation would be that of the cosine term, and its amplitude will be 3.984, an actual value given by the question itself.
