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Lina20 [59]
2 years ago
6

Suppose a random sample of 40 students from a university were asked their ages. The table below gives a summary of the reported

ages. Report and interpret a 95% confidence interval for the population mean. Assume the necessary conditions hold.
Age # of students
18 8
19 10
20 9
21 7
22 6

Group of answer choices

(18.0, 22.0). We are 95% confident that the mean age of university students in this sample is between 18 and 22.

(A.19.4, 20.3). We are 95% confident that the mean age of university students in this sample is between 19.4 and 20.3.

(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.

(19.4, 20.3). We are 95% confident that the mean age of university students is between 19.4 and 20.3.
Mathematics
1 answer:
fomenos2 years ago
4 0

Answer:

I think it is

Step-by-step explanation:

(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.

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Papessa [141]

Answer:

d = 10/72

Step-by-step explanation:

c and d vary inversely

c = k/d

Where,

k = constant of proportionality

d = 2/9 when c = 5

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5 = k ÷ 2/9

5 = k × 9/2

5 = 9k/2

Cross product

5*2 = 9k

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c = k/d

c = 10/9 ÷ d

c = 10/9 × 1/d

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find d when c = 8

c = 10/9d

8 = 10/9d

Cross product

8*9d = 10

72d = 10

d = 10/72

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Step-by-step explanation:

3 0
3 years ago
1/2 to the power of 5 equals
svp [43]

Answer:

1/32

Step-by-step explanation:

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3 years ago
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(x-3)^2 x=a number in this case
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Answer:

Step-by-step explanation:

Tear this apart piece by piece

15 -  8 = 7

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Add 4

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