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Lina20 [59]
2 years ago
6

Suppose a random sample of 40 students from a university were asked their ages. The table below gives a summary of the reported

ages. Report and interpret a 95% confidence interval for the population mean. Assume the necessary conditions hold.
Age # of students
18 8
19 10
20 9
21 7
22 6

Group of answer choices

(18.0, 22.0). We are 95% confident that the mean age of university students in this sample is between 18 and 22.

(A.19.4, 20.3). We are 95% confident that the mean age of university students in this sample is between 19.4 and 20.3.

(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.

(19.4, 20.3). We are 95% confident that the mean age of university students is between 19.4 and 20.3.
Mathematics
1 answer:
fomenos2 years ago
4 0

Answer:

I think it is

Step-by-step explanation:

(18.0, 22.0). We are 95% confident that the mean age of university students is between 18 and 22.

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Calculate the missing terms of the geometric sequence ...,3072, 7,2,7, 12,.... Select all that apply.
miskamm [114]

Answer:

The missing terms are 768, 192, 48.

Step-by-step explanation:

From the given geometric sequence

First term= a_1=3072

Fifth Term= a_5=12  

The general form of a geometric sequence is:

a_n=ar^(n-1)

here a_nis the nth term, a is the first term and r is the common ratio.

We will use the general form for term 5 to calculate the value of r.

So the general form for term 5 will be

a_5=3072* r^(5-1)

Putting the value of a_5

12=3072* r^4

r^4=  12/3072

r^4=  1/256

r^4=  1/[(4)^4]

Solving for r  

r=  1/4

Now  

a_2= ar^(2-1)

a_2=3072*r

a_2=3072*  1/4

a_2=768

a_3= ar^(3-1)

a_3=3072*r^2

a_3=3072*(1/4)^2

a_3=3072*  1/16

a_3=192

a_4= ar^(4-1)

a_4=3072*r^3

a_4=3072*(1/4)^3

a_4=3072*  1/64

a_4=48

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There needs to be a picture of the triangles
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since diameter is given, use the 2nd equation

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