Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
72 as Damon spend 2 and 15 minutes exercising so for the two dull hours you add 64 now that done and as 15 is 1/4 of 60 you add 8 which is 1/4 of 32 and get 72
Answer:
Option (D)
Step-by-step explanation:
Surface area of a square pyramid is determined from the formula,
Surface area = Area of the square base + 4(Area of one lateral triangular side)
Area of the base = (Side)²
= 8²
= 64 cm²
Area of one lateral triangle = 
= 
= 32 cm²
Therefore, surface area of the square pyramid = 64 + 4(32)
= 64 + 128
= 192 cm²
Therefore, Option (D) will be the correct option.