Name the following compound: CH3 - CH₂ - CH₂ - CH₂ - OH

Chemistry

1 answer:

Marina CMI [18]2 years ago

7 0

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

There are 4 carbon atoms in the chain, so it's prefix should be " But " and there are only sigma bonds, therefore the primary suffix will be " ane ", and the functional group attached to the end is " OH " denoting alcohol group, so the secondary suffix will be " ol "

Hence, the name of the compound will be ~

$\qquad \sf \dashrightarrow \:Butan - 1 - ol$

or simply

$\qquad \sf \dashrightarrow \: Butan ol$

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7. NH2CO2NH4(s) when heated to 450 K undergoes the following reaction to produce a system which reaches equilibrium: NH2CO2NH4(s

Taya2010 [7]

Answer:

Value of equilibrium constant is 0.0888

Explanation:

Both $NH_{3}$ and $CO_{2}$ are gaseous. Hence equilibrium constant depends upon partial pressures of $NH_{3}$ and $CO_{2}$ .

Initially no $NH_{3}$ and $CO_{2}$ were present.

Hence mole fraction of $NH_{3}$ and $CO_{2}$ at equilibrium can be calculated from coefficient of $NH_{3}$ and $CO_{2}$ in balanced equation.

Mole fraction of $NH_{3}$ = (number of moles of $NH_{3}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{2moles}{(2+1)moles}=\frac{2}{3}$

Mole fraction of $CO_{2}$ = (number of moles of $CO_{2}$ )/(total number of moles of $NH_{3}$ and $CO_{2}$ ) = $\frac{1moles}{(2+1)moles}=\frac{1}{3}$