Solution:
<span>1 L of solution and 1.03 g/mL = 1030 g/L </span>
<span>
1030 g/L time 10.5%
= 108.15 g of glucose/L</span>
And
<span>=108.15 g / 180.16 g/mol
= 0.6003 moles in 1L </span>
<span>=or 0.600 mol/kg</span>
Answer:
2.3 L
Explanation:
when you have this eqaution you use P1V1T2=P2V2T1.
since you are looking for volume of gas cylinder that means you are looking for V2.
so you have your given P= 1.0 atm, V=2.5L, T=298K.
They ask you to use STP or standard pressure and temperature.
STP P= 1atm, STP T=273 K
so you are looking for V2 meaning you are going to get V alone so your new equation is P1*V1*TS/ P2* T1= V2
so you now substitue so its now 1*273*2.5/ 1* 298= V
682.5/ 298= V
Lastly V= 2.2902 and you round to tenths so now you have
V= 2.3 L
Answer:
Los usos de la plata son cientos, sobre todo en procesos industriales, comerciales y hasta personales. Su resistencia a la corrosión la hace ideal para la elaboración de recipientes especiales o para recubrir otros metales.
Explanation:
The answer is <span>C. those with the same color</span>
Answer:
2
Explanation:
#1 is incorrect as there is no upward force that would balance the 5 N downward force
#3 is incorrect 2 is less than 5 = net force downward of 3 N
#4 is incorrect 5 is greater than three = 2 N net force going to the left and 2N going up
