Question

draw the organic product (if any) expected from the following reaction CH3CH2CH2OH + K2Cr2O7(aq) ---->H2SO4 is catalystNote: K2Cr2O7 is present in excess.

Answer 1

Answer:

The product will be propanoic acid .

Explanation:

Under the action of strong oxidizing agent that is potassium dichromate in an acidic medium primary oxidizes the primary alcohols into carboxylic acid .

$RCH_2OH+K_2Cr_2O_7\overset{H^+}\rightarrow RCOOH+H_2O$

So, when propanol is treated with potassium dichromate in an acidic medium it get converted into propanoic acid.

$CH_3-CH_2-CH_2-OH+K_2Cr_2O_7\overset{H^+}\rightarrow CH_3-CH_2-COOH+H_2O$