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sladkih [1.3K]
4 years ago
6

draw the organic product (if any) expected from the following reaction CH3CH2CH2OH + K2Cr2O7(aq) ---->H2SO4 is catalystNote:

K2Cr2O7 is present in excess.

Chemistry
1 answer:
m_a_m_a [10]4 years ago
6 0

Answer:

The product will be propanoic acid .

Explanation:

Under the action of strong oxidizing agent that is potassium dichromate in an acidic medium primary oxidizes the primary alcohols into carboxylic acid .

RCH_2OH+K_2Cr_2O_7\overset{H^+}\rightarrow RCOOH+H_2O

So, when propanol is treated with potassium dichromate in an acidic medium it get converted into propanoic acid.

CH_3-CH_2-CH_2-OH+K_2Cr_2O_7\overset{H^+}\rightarrow CH_3-CH_2-COOH+H_2O

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How many moles in 2.33E25 molecules of NO?
Sindrei [870]

Answer:

0.0258 mol <em>Answer</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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3 years ago
How are work and energy related
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5 0
3 years ago
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Genrish500 [490]

Answer:

The correct answer is 2.33g of H_{2}O, A

Explanation:

We can use basic stoich to get this question.

To start, lets convert our grams to moles in order to use our equation. 5.38g of O_{2} = (\frac{5.38}{2*15.999}) moles = 0.168136 moles.

We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of O_{2} to moles of H_{2}O. This gets us 0.129335 moles of H_{2}O.

Now lets convert to grams of H_{2}O by multiplying by the molar mass of H_{2}O. .129335*(1.008*2+15.999) = 2.32997g of H_{2}O

7 0
3 years ago
A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture
slava [35]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g 
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g  / 74.6 g/mol = 0.050 mol

Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles =  0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
                           = (0.372 mol / 0.652 mol) x 100%
                           = 57.06% 

Hence, mixture has 57.06% of NaCl as the mole percentage.
8 0
3 years ago
An ion that consists of 7 protons, 6 neutrons, and 10 electrons has a net charge of(I ) 4- (3) 3+(2) 3- (4) 4+
Flura [38]

Answer : The correct option is 2.

Explanation :

Number of protons = 7

Number of neutrons = 6

Number of electrons = 10

Protons are those which carries positive charge.

Electrons are those which carries negative charge.

Neutrons are those which do not carry any charge that means neutrons are neutral.

The net charge on an ion = Number of protons present in an ion + Number of electrons present in an ion

The net charge on an ion = (+7) + (-10) = -3

Therefore, the net charge on an ion is (-3).

5 0
4 years ago
Read 2 more answers
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