Answer:
El conjunto de los números reales está conformado por el conjunto de los números racionales y por el conjunto de los números irracionales. Son conjuntos disjuntos entre si. ... Un número es racional si puede ser representado como el cociente de dos números enteros.
Step-by-step explanation:
Let
x----------> charge per hour to rent a jet sky in dollars
y----------> the total cost to rent a jet sky in dollars
we know that
<u>First Jet Sky Company</u>
---------> equation 
<u>Second Jet Sky Company</u>
---------> equation 
we know that
To find the number of hours for which the costs are the same
equate equation
and equation 
The intersection both graphs is the solution of the problem
using a graph tool
see the attached figure
the intersection point is 
That means
For 
the cost of the rent is
in both companies
therefore
<u>the answer is</u>

Answer:
The force is 12 N
Step-by-step explanation:
* Lets explain how to solve the problem
- Direct variation is a relationship between two variables that can
be expressed by an equation in which one variable is equal to a
constant times the other
- If y ∝ x , then y = kx , where k is the constant of variation
* Lets solve the problem
- The force acting on the object varies directly with the object's
acceleration
∵ The force is F in newtons and a is the acceleration is m/s²
∴ F ∝ a
∴ F = ka
- To find k substitute F and a by the initial values of them
∵ A force of 10 N acts on a certain object, the acceleration of the
object is 5 m/s²
∵ F = 10 N when a = 5 m/s²
∵ F = ka
∴ 10 = k(5)
- Divide both sides by 5
∴ K = 2
- Substitute the value of k in the equation
∴ F = 2a
- Lets find the force when the acceleration is 6 m/s²
∵ a = 6 m/s²
∴ F = 2(6) = 12
* The force is 12 N
Step-by-step explanation:
Step 1: Write down the percent divided by 100 like this: percent 100.
Step 2: If the percent is not a whole number, then multiply both top and bottom by 10 for every number after the decimal point. ...
Step 3: Simplify (or reduce) the fraction<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>