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DIA [1.3K]
2 years ago
11

Math graphs Find the graph

Mathematics
1 answer:
Nadya [2.5K]2 years ago
3 0

Step-by-step explanation:

put the value of y and get the value of x.then plot it in graph.(try to get non fractional values)

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Today, 6 friends went out for lunch. Their total bill was $50.41 , including tax and gratuity. One of them ordered only soda and
Burka [1]

Answer:

50.41 minus 1.71 is 48.70 divided by 5 is 9.74

3 0
2 years ago
Someone pls help me
Nat2105 [25]
The answer should be AC+BC

We can answer this by applying the rule called "Greater angle, greater side". This is where in any triangle, the opposite side of the larger angle is also longer.

So in this question, first we have to find the largest 2 angles, which is ∠ABC and ∠BAC with measures of 120° and 35° respectively. Therefore, from the diagram, the opposite sides of the angles are AC and BC. 

Therefore, the answer should be AC+BC.
7 0
3 years ago
What is the answer ​
Reika [66]

Answer:

35 mi²

Step-by-step explanation:

Let's subdivide the figure, as shown.

The lower part is a rectangle whose area is (5 mi)(18 mi) = 90 mi².

The upper part is a trapezoid whose area is found by averaging the length and multiplying the result by the width (8 mi - 5 mi), or 3 mi.

Area of trapezoid:

     12 mi + 18 mi

  ------------------------  =  15 mi             Width of trapezoid = 3 mi

                2

Thus, the area of the trapezoid is (3 mi)(15 mi) = 45 mi²

and the total area of the entire figure is

45 mi² + 90 mi² = 135 mi²

3 0
3 years ago
I neeeeeeeeeeeeeed help
masya89 [10]

9514 1404 393

Answer:

  14 +2i

Step-by-step explanation:

For this sort of problem, you can treat i as though it were a variable. Combine like terms.

  (8 -7i) +(6 +9i) = (8 +6) +(-7 +9)i

  = 14 +2i

7 0
3 years ago
If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

3 0
3 years ago
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