I don't know how to delete a question how can I do that?
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Answer:
Step-by-step explanation:
The missing figure is attached.
For this exercise it is important to remember that, by definition, the opposite interior angles of an inscribed quadrilateral are supplementary, which means that their sum is 180 degrees.
Based on this, you can identify that the angle D and the angle B are opposite and, therefore, supplementary.
Knowing that, you can write the following equation:
Now you must solve for "x" in order to find its value. This is:
Then:
You know that:
Therefore, since you know the value of "x", you can substitute it into and then you must evaluate, in order to find the measure of the angle A. This is:
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = = 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!